Diabetes and chronic kidney disease (CKD) are two diseases that are increasingly burdening the senior population in the US. A large national sample of health care visits to the Veteran’s Health Administration system indicates that 9.1% of veterans in their 60s have stage 3-5 CKD. However, this rate is 14.1% among veterans in their 60s diagnosed with diabetes, and only 6.4% among veterans in their 60s without diabetes. Express these three percentages as probabilities for a randomly selected veteran 60-69 years of age.
Diabetes and chronic kidney disease (CKD) are two diseases that are increasingly burdening the senior population in the US. A large national sample of health care visits to the Veteran’s Health Administration system indicates that 9.1% of veterans in their 60s have stage 3-5 CKD. However, this rate is 14.1% among veterans in their 60s diagnosed with diabetes, and only 6.4% among veterans in their 60s without diabetes. Express these three percentages as probabilities for a randomly selected veteran 60-69 years of age.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Diabetes and chronic kidney disease (CKD) are two diseases that are increasingly burdening the senior population in the US. A large national sample of health care visits to the Veteran’s Health Administration system indicates that 9.1% of veterans in their 60s have stage 3-5 CKD. However, this rate is 14.1% among veterans in their 60s diagnosed with diabetes, and only 6.4% among veterans in their 60s without diabetes. Express these three percentages as probabilities for a randomly selected veteran 60-69 years of age.

Transcribed Image Text:Example 10.3:
Dead
Live
Sapling
Total
Western red cedar (RC)
0.02
0.10
0.08
0.20
Douglas fir (DF)
0.16
0.16
0.00
0.32
Western hemlock (WH)
023
0.21
0.04
0.48
Total
041
047
0.12
The "Total" row and column are obtained from the probabilities in the body of the table by the addition
rule. For example, the probability that a randomly selected tree is a western hemlock (WH) is
P(WH) = P(WH and dead) + P(WH and live) + P(WH and sapling)
= 0.23 +0.21 + 0.04 = 0.48
Now we are told that the tree selected is a sapling. That is, it is one of the 12% of all trees that fall in
the "Sapling" column of the table. The probability that a tree is a western hemlock, given the information
that the tree is a sapling, is the proportion of western hemlocks in the “Sapling" column:
0.04
P(WH | sapling):
0.33
0.12
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