dH VdP = dS T т (1) show that equation (1) leads to equation (2). please don't use any other equation but (1) in that setup не ;)T = V (1 – T3) ӘР -(2) I've done so far this (this is my work), can someone continue my work please for an upvote dH
dH VdP = dS T т (1) show that equation (1) leads to equation (2). please don't use any other equation but (1) in that setup не ;)T = V (1 – T3) ӘР -(2) I've done so far this (this is my work), can someone continue my work please for an upvote dH
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Please continue my work I've included in the image. show that equation (1) leads to equation (2) by replacing the L.H.S and R.H.S with the equations shown in the image. (this is what I've done so far)
![## Thermodynamic Derivation
### Equation (1):
\[
\frac{dH}{T} - V \frac{dP}{T} = dS
\]
The task is to show that equation (1) leads to equation (2) using no other equations.
### Equation (2):
\[
\left( \frac{\partial H}{\partial P} \right)_T = V(1 - T \beta)
\]
### Solution Process
1. **Start with the Left Hand Side (L.H.S):**
\[
\frac{dH}{T} = \left( \frac{\partial}{\partial P} \right)_H \left( \frac{1}{T} \right)
\]
Breaking it down further:
\[
= \frac{1}{T^2} \frac{1}{C_p} \left( \frac{\partial H}{\partial P} \right)_T
\]
2. **Proceed to the Right Hand Side (R.H.S):**
\[
\frac{V dP}{T} = \left( \frac{\partial}{\partial H} \right)_P \left( -\frac{V}{T} \right)
\]
Expanding it gives:
\[
= -\frac{1}{T} \frac{\partial V}{\partial H} |_P + \frac{V}{T^2} \frac{\partial T}{\partial H} |_P
\]
This completes the setup needed to transform equation (1) into equation (2). Further simplification or calculation may be needed to complete the derivation as requested.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F56e8b022-9dd8-4fb4-b3ca-fd6588a1a301%2Fad0f44ee-fbbb-4f7a-a5e3-771a5e4adc49%2Fek1ja5s_processed.png&w=3840&q=75)
Transcribed Image Text:## Thermodynamic Derivation
### Equation (1):
\[
\frac{dH}{T} - V \frac{dP}{T} = dS
\]
The task is to show that equation (1) leads to equation (2) using no other equations.
### Equation (2):
\[
\left( \frac{\partial H}{\partial P} \right)_T = V(1 - T \beta)
\]
### Solution Process
1. **Start with the Left Hand Side (L.H.S):**
\[
\frac{dH}{T} = \left( \frac{\partial}{\partial P} \right)_H \left( \frac{1}{T} \right)
\]
Breaking it down further:
\[
= \frac{1}{T^2} \frac{1}{C_p} \left( \frac{\partial H}{\partial P} \right)_T
\]
2. **Proceed to the Right Hand Side (R.H.S):**
\[
\frac{V dP}{T} = \left( \frac{\partial}{\partial H} \right)_P \left( -\frac{V}{T} \right)
\]
Expanding it gives:
\[
= -\frac{1}{T} \frac{\partial V}{\partial H} |_P + \frac{V}{T^2} \frac{\partial T}{\partial H} |_P
\]
This completes the setup needed to transform equation (1) into equation (2). Further simplification or calculation may be needed to complete the derivation as requested.
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