Determine the upper-tail critical value ta/2 in each of the following circumstances.a. 1-a=0.95, n = 13d. 1-q=0.95, n = 38b. 1-a=0.99, n = 13e. 1-α=0.90, n=62c. 1-α=0.95, n = 46Click here to view page 1 of the table of critical values for the t distribution.Click here to view page 2 of the table of critical values for the t distribution.a. t=(Round to four decimal places as needed.)b. t=(Round to four decimal places as needed.)c. t=(Round to four decimal places as needed.)(Round to four decimal places as needed.)d. t=e.t=(Round to four decimal places as needed.)View instructor tip Help me solve thisType here to search-BQ.SE$Get more help.4CODIBR5T82°F55U0E Construct an 80% confidence interval to estimate the population mean when x = 55 and s = 14.4 for the sample sizes below.a) n = 24b) n=45c) n=56a) The 80% confidence interval for the population mean when n = 24 is from a lower limit of to an upper limit of(Round to two decimal places as needed.)b) The 80% confidence interval for the population mean when n = 45 is from a lower limit of(Round to two decimal places as needed.)to an upper limit ofc) The 80% confidence interval for the population mean when n = 56 is from a lower limit of(Round to two decimal places as needed.)to an upper limit ofHelp me solve thisView an exampleAsk my instructorOHType here to search82°F0

As per our guidelines we are suppose to answer only one question 1)a)Given1-α=0.95n=13

Answered: Determine the upper-tail critical value…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A manufacturer is interested in the output voltage of a power supply used in a PC. Output voltage is assumed to be normally distributed, with standard deviation 0.25 V, and the manufacturer wished to test Hg: H = 8 against H1: u # 8, using n = 10 units. Statistical Tables and Charts (a) The critical region is 8.14. Find the value of a. Round the answer to 3 decimal places. a = 1 eTextbook and Media (b) Find the power of the test for detecting a true mean output voltage of 8.08 V. Round the answer to 3 decimal places. The power of the test is 1 eTextbook and Media
A population of values has a normal distribution with μ=204.6μ=204.6 and σ=17σ=17. You intend to draw a random sample of size n=92n=92.Find P67, which is the score separating the bottom 67% scores from the top 33% scores.P67 (for single values) = IncorrectFind P67, which is the mean separating the bottom 67% means from the top 33% means.P67 (for sample means) = Enter your answers as numbers accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Do one of the following, as appropriate: (a) Find the critical value za/2, (b) find the critical value ta/2, (c) state that neither the normal nor the t distribution applies. 98%; n = 7; 0 = 27; population appears to be normally distributed. Seleccione una: O A. Za2 = 2.33 B. Za2 = 2.05 C. ta2 = 2.575 %3D D. ta2 = 1.96 O O
A population of values has a normal distribution with μ=106.2μ=106.2 and σ=61σ=61. You intend to draw a random sample of size n=85n=85.Find P93, which is the score separating the bottom 93% scores from the top 7% scores.P93 (for single values) = Find P93, which is the mean separating the bottom 93% means from the top 7% means.P93 (for sample means) = Enter your answers as numbers accurate to 1 decimal place.
Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. TInterval (13.046,22.15) E Click the icon to view a t distribution table. x= 17.598 Sx = 16.01712719 n= 50 a. What is the number of degrees of freedom that should be used for finding the critical value t2? df = (Type a whole number.) b. Find the critical value t2 corresponding to a 95% confidence level. a/2 = (Round to two decimal places as needed.) c. Give a brief general description of the number of degrees of freedom. O A. The number of degrees of freedom for a collection of sample data is the number of sample values that can vary after certain restrictions have been imposed on all data values. OB. The number of degrees of freedom for a collection of sample data is the number of unique, non-repeated sample values. O C. The number of degrees of freedom for a collection of sample data is the number of sample values that are determined after certain…
A population of values has a normal distribution with μ=185.7μ=185.7 and σ=57.5σ=57.5. You intend to draw a random sample of size n=57n=57.Find P25, which is the score separating the bottom 25% scores from the top 75% scores.P25 (for single values) = Find P25, which is the mean separating the bottom 25% means from the top 75% means.P25 (for sample means) =
Make sure to do the rounding and double check the answers please.
Find the appropriate critical F-value for each of the following using the F-distribution table. a. D, = 20, D, = 12, a = 0.05 b. D, = 9, D2 = 24, a = 0.05 c. D, = 20, D2 = 12, a = 0.025 ..... a. The critical F-value when D, = 20, D, = 12, and a = 0.05 is (Round to three decimal places as needed.) b. The critical F-value when D, = 9, D, = 24, and a = 0.05 is (Round to three decimal places as needed.) c. The critical F-value when D, = 20, D2 = 12, and a = 0.025 is (Round to three decimal places as needed.)
A population of values has a normal distribution with μ=116.3μ=116.3 and σ=27.5σ=27.5. You intend to draw a random sample of size n=249n=249.Find the probability that a single randomly selected value is greater than 117.3.P(X > 117.3) = Find the probability that a sample of size n=249n=249 is randomly selected with a mean greater than 117.3.P(¯xx¯ > 117.3) = Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 66 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 123 kWh. At a = 0.10, can you support the claim? Complete parts (a) through (e). B. The critical value is 1.28 Identify the rejection region(s). Select the correct choice below. O A. The rejection regions are z 1.28 OB. The rejection region is z > 1.28 OC. The rejection region is z< 1.28. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z = (Round to two decimal places as needed.)
Use the information given in the table below to find a 95% Prediction Interval for y when x = 10. n = 20 x_bar = 15 %3D beta0_hat = 53 SSXX = 62 beta1_hat = - 4.5 S = 9 (- 14.79, 30.79) (-0.57, 16.57) (-10.25, 26.25) O (- 4.73, 20.73)
Assuming α= 0.05, what is the critical t value for the following distributions: df = 10, two-tailed test 2. df = 30, one tailed (lower tail) 3. df = 15, one tailed (upper tail)

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