Determine the upper-tail critical value ta/2 in each of the following circumstances.a. 1-a=0.95, n = 13d. 1-q=0.95, n = 38b. 1-a=0.99, n = 13e. 1-α=0.90, n=62c. 1-α=0.95, n = 46Click here to view page 1 of the table of critical values for the t distribution.Click here to view page 2 of the table of critical values for the t distribution.a. t=(Round to four decimal places as needed.)b. t=(Round to four decimal places as needed.)c. t=(Round to four decimal places as needed.)(Round to four decimal places as needed.)d. t=e.t=(Round to four decimal places as needed.)View instructor tip Help me solve thisType here to search-BQ.SE$Get more help.4CODIBR5T82°F55U0E Construct an 80% confidence interval to estimate the population mean when x = 55 and s = 14.4 for the sample sizes below.a) n = 24b) n=45c) n=56a) The 80% confidence interval for the population mean when n = 24 is from a lower limit of to an upper limit of(Round to two decimal places as needed.)b) The 80% confidence interval for the population mean when n = 45 is from a lower limit of(Round to two decimal places as needed.)to an upper limit ofc) The 80% confidence interval for the population mean when n = 56 is from a lower limit of(Round to two decimal places as needed.)to an upper limit ofHelp me solve thisView an exampleAsk my instructorOHType here to search82°F0

As per our guidelines we are suppose to answer only one question 1)a)Given1-α=0.95n=13

Answered: Determine the upper-tail critical value…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Determine the upper-tail critical value to/2 in each of the following circumstances. a. 1-α = 0.99, n = 64 d. 1 -α = 0.99, n = 8 e. 1-α = 0.90, n = 44 b. 1-α = 0.95, n = 64 c. 1-α = 0.99, n = 18 Click here to view page 1 of the table of critical values for the t distribution. Click here to view page 2 of the table of critical values for the t distribution.
feeling lost on 5d and unable to get answer
Refer to the accompanying data display that results from a sample of airport data speeds in Mbps. Complete parts (a) through (c) below. TInterval (13.046,22.15) E Click the icon to view a t distribution table. x= 17.598 Sx = 16.01712719 n= 50 a. What is the number of degrees of freedom that should be used for finding the critical value t2? df = (Type a whole number.) b. Find the critical value t2 corresponding to a 95% confidence level. a/2 = (Round to two decimal places as needed.) c. Give a brief general description of the number of degrees of freedom. O A. The number of degrees of freedom for a collection of sample data is the number of sample values that can vary after certain restrictions have been imposed on all data values. OB. The number of degrees of freedom for a collection of sample data is the number of unique, non-repeated sample values. O C. The number of degrees of freedom for a collection of sample data is the number of sample values that are determined after certain…
I need a, b , c
Determine the upper-tail critical value t2 in each of the following circumstances. a. 1-a = 0.90, n = 34 b. 1- a = 0.99, n = 34 c. 1- a = 0.90, n = 24 Click here to view page 1 of the table of critical values for the t distribution. Click here to view page 2 of the table of critical values for the t distribution. d. 1-a = 0.90, n = 45 e. 1-a = 0,95, n= 57 a. t = (Round to four decimal places as needed.)
To compare the dry braking distances from 30 to 0 miles per hour for two makes of automobiles, a safety engineer conducts braking tests for 35 models of Make A and 35 models of Make B. The mean braking distance for Make A is 43 feet. Assume the population standard deviation is 4.6 feet. The mean braking distance for Make B is 46 feet. Assume the population standard deviation is 4.5 feet. At α=0.10, can the engineer support the claim that the mean braking distances are different for the two makes of automobiles? Assume the samples are random and independent, and the populations are normally distributed. The critical value(s) is/are Find the standardized test statistic z for μ1−μ2.
For 50 randomly selected speed dates, attractiveness ratings by males of their female date partners (x) are recorded along with the attractiveness ratings by females of their male date partners (y); the ratings range from 1 to 10. The 50 paired ratings yield x = 6.4, y = 5.9, r= - 0.319, P-value = 0.024, and y = 8.29 – 0.379x. Find the best predicted value of y (attractiveness rating by female of male) for a date in which the attractiveness rating by the male of the female is x = 8. Use a 0.10 significance level. ..... The best predicted value of y when x= 8 is (Round to one decimal place as needed.)
Show step by step 1 Simulate the failure times of 100 units randomly selected from a Weibull distributionwith characteristic life θ = 100 and shape parameter α = 3. Plot the histogram ofthese 100 data points and comment on this histogram. 2. Suppose the data of the last question came from a life testing but the test was stoppedat the 50-th failure. Re-organize the data set and re-plot the histogram. Compare thisplot with the previous plot and comment on these plots. Show step by step
Match each Test Situation with the correct Critical Value. For a two-sided test, find only the positive value. Test Situation Two samples, 1 = 25.3, I2 H.: P1 - 2 po, and a 0.01 %3D Two samples, n = 28, Ha: µd > 0, and a 0.01 dv One sample, ni = - 35, п2 41, Ha: p1 – p2 0, and a = 0.01 %3D %3D One sample of x's and y's, n = 114, Ha: p < 0, and a = 0.001 One sample, o is known, n = 68, Ha:µ # Ho, and a = 0.05 One sample, o is unknown, n = 76, H. : µ < Ho, and a 0.05 Critical Value a. 1.960 b. -3.165 C. 2.473 d. 2.326 e. 2.576 f. -1.294 g. -1.665 h. 2.426
Use the information given in the table below to find a 95% Prediction Interval for y when x = 10. n = 20 x_bar = 15 %3D beta0_hat = 53 SSXX = 62 beta1_hat = - 4.5 S = 9 (- 14.79, 30.79) (-0.57, 16.57) (-10.25, 26.25) O (- 4.73, 20.73)
Assuming α= 0.05, what is the critical t value for the following distributions: df = 10, two-tailed test 2. df = 30, one tailed (lower tail) 3. df = 15, one tailed (upper tail)
1. Find the critical Values 2. Compute the test value

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