**Hypothesis Testing Example****Scenario:**A company claims that the mean monthly residential electricity consumption in a certain region exceeds 860 kiloWatt-hours (kWh). You want to test this claim. You have a random sample of 66 residential customers, with a mean monthly consumption of 900 kWh. Assume the population standard deviation is 123 kWh. With a significance level (\( \alpha \)) of 0.10, can you support the claim? Follow steps (a) through (e).**(a) Critical Value:**- **Chosen Option:** B. The critical value is 1.28**(b) Identify the Rejection Region(s):**- **Chosen Option:** B. The rejection region is \( z > 1.28 \)**(c) Standardized Test Statistic:**- The standardized test statistic \( z \) needs to be calculated.- The problem prompt instructs rounding the value to two decimal places once computed. To solve this, use the formula for the standardized test statistic:\[z = \frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}}}\]Where:- \( \bar{x} = 900 \) (sample mean)- \( \mu = 860 \) (population mean under the null hypothesis)- \( \sigma = 123 \) (population standard deviation)- \( n = 66 \) (sample size)Compute the test statistic to decide whether to reject the null hypothesis in favor of the alternative claim that the mean consumption is indeed greater than 860 kWh.

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A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 66 residential cust mean monthly consumption of 900 kWh. Assume the population standard deviation is 123 kWh. At a= 0.10, can you support the claim? Complete parts (a) through (e) B. The critical value is 1.28 Identify the rejection region(s). Select the correct choice below. O A. The rejection regions are z< -1.28 and z> 1.28. YB. The rejection region is z> 1.28 OC. The rejection region is z <1.28. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z=

A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 66 residential cust mean monthly consumption of 900 kWh. Assume the population standard deviation is 123 kWh. At a= 0.10, can you support the claim? Complete parts (a) through (e) B. The critical value is 1.28 Identify the rejection region(s). Select the correct choice below. O A. The rejection regions are z< -1.28 and z> 1.28. YB. The rejection region is z> 1.28 OC. The rejection region is z <1.28. (c) Find the standardized test statistic. Use technology. The standardized test statistic is z=

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 122 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H₂. Choose the correct answer below. OA. Ho: 5900 Ha: >900 (claim) OC. Ho: >870 (claim) Η:15 870 O E. Ho: >900 (claim) H₂900 OB. Ho: H=870 (claim) H₂H870 O D. Ho: H=900 OF. Ho: H≤ 870 H: 900 (claim) (Round to two decimal places as needed.) ⒸA. The critical values are t OB. The critical value is. Identify the rejection region(s). Select the correct choice below. (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. OA. The rejection regions are z 1.64. B. The rejection region…
more than 880 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthly A company claims that the mean monthly residential electricity consumption in a certain region i consumption of 920 kWh. Assume the population standard deviation is 129 kWh. At a = 0.01, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H. Choose the correct answer below. O A. Ho: µ= 880 (claim) B. Ho: us 880 H: u#880 H:u> 880 (claim) OC. Ho: u> 920 (claim) O D. Ho: uS920 H:u>920 (claim) H: us920 O E. Ho: u> 880 (claim) ΟΕ H : μ= 920 H:ps 880 Ha:u#920 (claim) (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) O A. The critical values are ± YB. The critical value is 2.33. Identify the rejection region(s). Select the correct choice below. O A. The rejection region is z…
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A company claims that the mean monthly residential electricity consumption in a certain region is more than 870 kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean monthly consumption of 900 kWh. Assume the population standard deviation is 121 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (a) Identify Ho and H₂. Choose the correct answer below. OA. Ho: >870 (claim) H₂: H≤870 OC. Ho: μ≤900 Ha: >900 (claim) E. Ho: H≤870 H: >870 (claim) OB. Ho: H=900 OA. The rejection region is z> 1.64. OB. The rejection region is z 1.64. H₂: #900 (claim) OD. Ho: H=870 (claim) Ha: 870 OF. Ho: >900 (claim) Ha: HS900 (b) Find the critical value(s) and identify the rejection region(s). Select the correct choice below and fill in the answer box within your choice. Use technology. (Round to two decimal places as needed.) A. The critical value is 1.64. OB. The critical values are t Identify the rejection…
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PLEASE ANSWER ALL THE PARTS OF QUESTION (THIS IS NOT A HRADED ASSIGNMENT)
A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean monthly consumption of 880 kWh. Assume the population standard deviation is 126 kWh. At α=0.01, can you support the claim? Complete parts (a) through (e). Also find the critical values.
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A company claims that the mean monthly residential electricity consumption in a certain region is more than 860 kiloWatt-hours (kWh). You want to test this claim. You find that a random sample of 60 residential customers has a mean monthly consumption of 880 kWh. Assume the population standard deviation is 123 kWh. At a = 0.05, can you support the claim? Complete parts (a) through (e). (Round to two decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Fail to reject Ho because the standardized test statistic is in the rejection region. O B. Reject Ho because the standardized test statistic is in the rejection region. O C. Fail to reject Ho because the standardized test statistic is not in the rejection region. O D. Reject Ho because the standardized test statistic is not in the rejection region. (e) Interpret the decision in the context of the original claim. At the 5% significance level, there enough evidence to V the claim that the mean…