Determine the ultimate load distribution acting on all beams and girders in the given floor framing below. Assume that the supports are simply supported. Compute for the reactions and loads in each beam. Assume unit weight of concrete to be 23.6 kN/m³. Always simplify your load distributions (distributed loads acting on the same points/locations should be added up). Monolithic Floor All concrete slabs, t = 100 mm All concrete beams, b = 250 mm; h = 500 mm All concrete columns, 300 mm x 300mm Superimposed Loads Floor Finish: Ceiling: Ceramic tile ½ inch mortar Frame Partition: Exterior Walls Wood furring Gypsum board 14 inch thick Mechanical Duct Allowance (MDA) Utilities: twice the weight of MDA Live Load Wood, studs with gypsum board h=2.8m 5m A H 3m Normal Unit Weight Concrete Masonry/ Concrete Hollow Blocks, CHB 4 inch thick with plastering on both faces, full grout height=3m (no interior walls) Residential NOTE: REFER TO NSCP 2015 CHAPTER 2 FOR THE MINIMUM DESIGN LOADS. USE LRFD LOAD FACTORS: 1.2 DL + 1.6 LL B G 2m C F 2.5m D

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Determine the ultimate load distribution acting on all beams and girders in the given floor framing below.
Assume that the supports are simply supported. Compute for the reactions and loads in each beam. Assume
unit weight of concrete to be 23.6 kN/m³. Always simplify your load distributions (distributed loads acting on
the same points/locations should be added up).
Monolithic Floor
All concrete slabs, t = 100 mm
All concrete beams, b = 250 mm; h= 500 mm
All concrete columns, 300 mm x 300mm
Superimposed Loads
Floor Finish:
Ceiling:
Ceramic tile ½ inch mortar
Frame Partition:
Exterior Walls
Wood furring
Gypsum board 14 inch thick
Mechanical Duct Allowance (MDA)
Utilities: twice the weight of MDA
Live Load
Wood, studs with gypsum board h=2.8m
5m
A
H
3m
Normal Unit Weight Concrete Masonry/ Concrete Hollow Blocks, CHB
4 inch thick with plastering on both faces, full grout
height=3m (no interior walls)
Residential
NOTE: REFER TO NSCP 2015 CHAPTER 2 FOR THE MINIMUM DESIGN LOADS.
USE LRFD LOAD FACTORS: 1.2 DL + 1.6 LL
B
G
2m
C
F
2.5m
D
Transcribed Image Text:Determine the ultimate load distribution acting on all beams and girders in the given floor framing below. Assume that the supports are simply supported. Compute for the reactions and loads in each beam. Assume unit weight of concrete to be 23.6 kN/m³. Always simplify your load distributions (distributed loads acting on the same points/locations should be added up). Monolithic Floor All concrete slabs, t = 100 mm All concrete beams, b = 250 mm; h= 500 mm All concrete columns, 300 mm x 300mm Superimposed Loads Floor Finish: Ceiling: Ceramic tile ½ inch mortar Frame Partition: Exterior Walls Wood furring Gypsum board 14 inch thick Mechanical Duct Allowance (MDA) Utilities: twice the weight of MDA Live Load Wood, studs with gypsum board h=2.8m 5m A H 3m Normal Unit Weight Concrete Masonry/ Concrete Hollow Blocks, CHB 4 inch thick with plastering on both faces, full grout height=3m (no interior walls) Residential NOTE: REFER TO NSCP 2015 CHAPTER 2 FOR THE MINIMUM DESIGN LOADS. USE LRFD LOAD FACTORS: 1.2 DL + 1.6 LL B G 2m C F 2.5m D
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