Determine the structure of an alcohol with the molecular formula CH₁O that exhibits the following 13C NMR spectra. 10 DEPT - 135 DEPT - 90 Broadband 95 95 90 85 80 75 70 10 65 www. 60 60 55 50 45 40 35 30 25 f1 (ppm) 220 20 15 10 5 0
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- Compound A has molecular formula C7H7X. Its 1H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C-NMR shows five signals. The mass spectrum of A shows a peak at m/z = 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The 1H-NMR spectrum of C shows…Use the 1H NMR and IR data to determine the structure of each compound.Compound A has molecular formula C7H7X. Its ¹H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C- NMR shows five signals. The mass spectrum of A shows a peak at m/z 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The ¹H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The ¹H-NMR spectrum of C shows…
- The 'H NMR and 13C spectra of a compound with a molecular formula of C6H12O2 are shown below. 1. Name the compound in the textbox below. 2. Draw a possible structure for this compound. 1Η NMR 2H 2H 2H 3HPPM 3H 13C NMR 220 200 100 140 100 120 PPMA compound with molecular formula C3H8O produces a broad signal between 3200 and 3600 cm³¹ in its IR spectrum and produces two signals in its 13C NMR spectrum. Draw the structure of the compound. Draw Your SolutionDraw the structure of a compound with the molecular formula C8H₁0 that exhibits five signals in its ¹3C NMR spectrum, four of which appear between 100 and 150 ppm.
- Compound X (molecular formula C10H12O) was treated with NH2NH2,−OH to yield compound Y (molecular formula C10H14). Based on the 1H NMR spectra of X and Y given below, what are the structures of X and Y?Compound P has molecular formula C5H9ClO2. Deduce the structure of P from its 1H and 13C NMR spectra.What is the structure of the compound with the formula C8H10O has six signals in its 13C-NMR spectrum. The IR spectrum shows signals at 3400 and 2900 cm-1, the 1H-NMR spectrum is: 1.19 ppm (3H triplet) 2.58 ppm (2H quartet) 4.65 ppm (1H broad singlet) 6.07 ppm (2H doublet) 7.05 ppm (2H doublet)
- A compound with molecular formula C3H8O produces a broad signal between 3200 and 3600 cm1 in its IR spectrum and produces two signals in its 1°C NMR spectrum. Draw the structure of the compound.Thymol (molecular formula C10H14O) is the major component of the oil of thyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and 1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose a possible structure for thymol.A compound with molecular formula C8H8O3 exhibits the following IR, 1H NMR and 13C NMR spectra. Deduce the structure of this compound.