The 'H NMR and 13C spectra of a compound with a molecular formula of C,H1202 are shown below. 1. Name the compound in the textbox below. 2. Draw a possible structure for this compound. 1Η NMR 2H 2H 2H 3HPPM 3H 13C NMR 220 200 100 120 PPM 100 100 00

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### Analysis of ^1H NMR and ^13C NMR Spectra

**Objective:**
Analyze the provided ^1H NMR and ^13C NMR spectra for a compound with the molecular formula \( \text{C}_6\text{H}_{12}\text{O}_2 \).

#### ^1H NMR Spectrum (Proton NMR):

- The ^1H NMR spectrum reveals the following peaks:
  - A quartet around \( \delta = 3.7 \) ppm, integrating for 2 hydrogens (2H).
  - A triplet around \( \delta = 2.3 \) ppm, integrating for 2 hydrogens (2H).
  - A triplet around \( \delta = 2.1 \) ppm, integrating for 2 hydrogens (2H).
  - A singlet around \( \delta = 1.1 \) ppm, integrating for 3 hydrogens (3H).

- Peaks illustrate proton environments and multiplicity (splitting):
  - The peak at 3.7 ppm is indicative of a methylene group (-CH2-) adjacent to an electronegative atom such as oxygen (O).
  - The peak at 2.3 ppm can signify protons ( methylene group adjacent to a carbonyl group (C=O)).
  - The peak at 2.1 ppm indicates another methylene group.
  - The peak at 1.1 ppm usually represents a methyl group (-CH3).

#### ^13C NMR Spectrum (Carbon NMR):

- The ^13C NMR spectrum displays the following chemical shifts:
  - Signal around \( \delta = 205 \) ppm.
  - Signal around \( \delta = 65 \) ppm.
  - Signal around \( \delta = 34 \) ppm.
  - Multiple signals between \( \delta = 20-40 \) ppm.

- The peak at 205 ppm likely corresponds to a carbonyl carbon (C=O).
- The peak at 65 ppm suggests a carbon attached to an electronegative atom such as oxygen.
- The peaks between 20-40 ppm can be associated with methylene and methyl carbons.

**Conclusions:**

1. The molecular formula C6H12O2 suggests the presence of possibly ester functionality.
2. Combining the ^1H and ^13C NMR data, a
Transcribed Image Text:### Analysis of ^1H NMR and ^13C NMR Spectra **Objective:** Analyze the provided ^1H NMR and ^13C NMR spectra for a compound with the molecular formula \( \text{C}_6\text{H}_{12}\text{O}_2 \). #### ^1H NMR Spectrum (Proton NMR): - The ^1H NMR spectrum reveals the following peaks: - A quartet around \( \delta = 3.7 \) ppm, integrating for 2 hydrogens (2H). - A triplet around \( \delta = 2.3 \) ppm, integrating for 2 hydrogens (2H). - A triplet around \( \delta = 2.1 \) ppm, integrating for 2 hydrogens (2H). - A singlet around \( \delta = 1.1 \) ppm, integrating for 3 hydrogens (3H). - Peaks illustrate proton environments and multiplicity (splitting): - The peak at 3.7 ppm is indicative of a methylene group (-CH2-) adjacent to an electronegative atom such as oxygen (O). - The peak at 2.3 ppm can signify protons ( methylene group adjacent to a carbonyl group (C=O)). - The peak at 2.1 ppm indicates another methylene group. - The peak at 1.1 ppm usually represents a methyl group (-CH3). #### ^13C NMR Spectrum (Carbon NMR): - The ^13C NMR spectrum displays the following chemical shifts: - Signal around \( \delta = 205 \) ppm. - Signal around \( \delta = 65 \) ppm. - Signal around \( \delta = 34 \) ppm. - Multiple signals between \( \delta = 20-40 \) ppm. - The peak at 205 ppm likely corresponds to a carbonyl carbon (C=O). - The peak at 65 ppm suggests a carbon attached to an electronegative atom such as oxygen. - The peaks between 20-40 ppm can be associated with methylene and methyl carbons. **Conclusions:** 1. The molecular formula C6H12O2 suggests the presence of possibly ester functionality. 2. Combining the ^1H and ^13C NMR data, a
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