At 25 °C, calculate the standard free energy change for the reaction as written. 1,3-Bisphosphoglycerate + ADP →ATP + 3-Phosphoglycerate + H+: AH = 41.02 kJ/mol and AS = 0.3030 kJ/molk. All answers should be in units of kJ/mol Type your answer...
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At 25 oC, calculate the standard free energy change for the reaction as written.
1,3-Bisphosphoglycerate + ADP →ATP + 3-Phosphoglycerate + H+:
ΔH = 41.02 kJ/mol and ΔS = 0.3030 kJ/molK.
All answers should be in units of kJ/mol
Step by step
Solved in 2 steps
- Another step in the metabolism of glucose, which occurs after the formation of glucose6-phosphate, is the conversion of fructose6-phosphate to fructose1,6-bisphosphate(bis meanstwo): Fructose6-phosphate(aq) + H2PO4(aq) fructose l,6-bisphosphate(aq) + H2O() + H+(aq) (a) This reaction has a Gibbs free energy change of +16.7 kJ/mol of fructose6-phosphate. Is it endergonic or exergonic? (b) Write the equation for the formation of 1 mol ADP fromATR for which rG = 30.5 kJ/mol. (c) Couple these two reactions to get an exergonic process;write its overall chemical equation, and calculate theGibbs free energy change.At what temperature is this reaction at equilibrium? 1,3-Bisphosphoglycerate + ADP →ATP + 3-Phosphoglycerate + H+: ΔH = 41.02 kJ/mol and ΔS = 0.3030 kJ/molK. All answers should be in units of KelvinCalculate the equilibrium constants Keqo for the following reactions, using the standard free energy changes given below. (Note: if your calculation produces an overflow error, give the answer as a power of e.)a) Glucose + 6O2 --> 6CO2 + 6H2O (–2,840 kJ/mol)b) ATP + H2O --> ADP + Pi (–30.5 kJ/mol)c) Ethyl Acetate + H2O --> Ethanol + Acetate (+19.6 kJ/mol)
- For the triose phosphate catalyzed reaction: dihydroxyacetone phosphate <--> glyceraldehyde-3-phosphate the standard change in Gibbs free energy is ΔG'º=7.53 kJ/mol. Calculate the ΔG for this reaction at 298K when the concentration of dihydroxyacetone phosphate is 0.161 M and the concentration of glyceraldehyde-3-phosphate is 0.00163 M.Given the following data: 2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(l) ΔG0= -6399 kJ C(s) + O2(g) → CO2(g) ΔG0= -394 kJ H2(g) + ½O2(g) → H2O(l) ΔG0= -237 kJ Calculate the ΔG0rxn for the reaction 6 C(s) + 3 H2(g) → C6H6(l)The standard free energy change for the reaction CH4(g)+2O2(g) -> CO2(g) + 2H2O(l) is -194.8 kcal at 25ºC and -191.82 kcal at 75ºC. Calculate the heat of reaction at 25ºC.Ans: -212.6 kcal
- In glycolysis, the reaction of glucose (Glu) to form glucose-6-phosphate (G6P) requires ATP to be present as described by the following equation: Glu+ ATP→G6) + ADP AG° = - 17KJ In this process, ATP becomes ADP summarized by the following equation: ATP→ ADP A G° =- 30 kJ What is the standard free energy change for the following reaction: Glu →G6P AG° =? A 17 k) B) -13 k) c) 13 kJ -17 kJThe Keq for the isomerization of glucose-6-phosphate to fructose-6-phosphate is 0.504. What is the ΔG for the reaction if the concentration of glucose-6-phosphate is 0.01 M and the concentration of fructose-6-phosphate is 0.05 M? This reaction is in the cell (this is your temperature = 30 degree celcius ). the answer should be 0.588 kcal/mol - please show all steps I am not sure how to get that answer1. Statement 1: beside its value for jewelries currency and electronics gold is also important in the health profession. Statement 2: Salts of Au+ is used in the treatment of certain types of rheumatoid arthritis2.Statement 1: Cellular restoration allows organisms to liberate the energy stored in the chemical bonds of glucose. Statement 2: C6H12O6 + 6O2 --> 6CO2 + 6H2O + 36 ATP, In this reaction glucose is reduce and oxygen is oxidized.3. Statement 1: The reaction of a metal with either an acid or a metal salt is called displacement reactions because the ion in the solution is to replace through reduction of an element. Statement 2: When metals undergo displacement reactions with acids, salts and hydrogen gas is produced. A - If the first statement is TRUE and the second statement is FALSE B - If the first statement is FALSE and the second statement is TRUE C - If both statements are TRUE D - If both statements are FALSE
- The standard free energy change for the reaction catalyzed by phosphoglucomutase is -7.1kJ/mol, (a) Calculate the equilibrium constant for the reaction, (b) Calculate ΔG at 37°C when the concentration of glucose-1-phosphate is 1-mM and the concentration of glucose-6-phosphate is 25-mM, (c) Is the reaction spontaneous under these conditions?Energy from ATP hydrolysis drives many nonspontaneouscell reactions:AT P⁴⁻(aq) +H₂O(l) ⇌ADP³⁻(aq) +HPO₄²⁻(aq) +H(aq) ΔG°'=-30.5 kJ Energy for the reverse process comes ultimately from glucose metabolism:C₆H₁₂O₆(s)+ 6O₂g) →6CO₂(g) +6H₂O(l)(a) Find K for the hydrolysis of ATP at 37°C.(b) Find ΔG'°ᵣₙₓ for metabolism of 1 mol of glucose. (c) How many moles of ATP can be produced by metabolism of1 mol of glucose? (d) If 36 mol of ATP is formed, what is the actual yield?Calculate AH for the reaction C(graphite) + 2H2(9) → CHạ using the following data: C(graphite) + O2(g) → CO2(9) AH = -393.5 kJ H2«9) + 02c9) → H20m H201) AH = -285.8 kJ ΔΗ- CH49) + 202(9) → CO2(g) + 2H201) AH = -890.4 kJ