Determine the output of the following program: #include using namespace std; void cdabs(int); void cdabs(float); void cdabs(double); int main(){ cdabs (3); cin.ignore(); return 0; } void cdabs(int x){ cout <« x « " is an int" « endl; } void cdabs(float x){ cout <« x « " is a float" « endl; } void cdabs(double x){ cout <« x << " is a double" <« endl;

Database System Concepts
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ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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---

### Understanding Function Overloading in C++

**Objective:** Determine the output of the following program.

```cpp
#include <iostream>
using namespace std;

void cdabs(int);
void cdabs(float);
void cdabs(double);

int main() {
    cdabs(3);
    cin.ignore();
    return 0;
}

void cdabs(int x) {
    cout << x << " is an int" << endl;
}

void cdabs(float x) {
    cout << x << " is a float" << endl;
}

void cdabs(double x) {
    cout << x << " is a double" << endl;
}
```

**Explanation:**

This C++ program demonstrates function overloading—a feature that allows multiple functions with the same name but with different parameter types.

- **Function Declarations:**
  - `void cdabs(int);` - Declares a function that takes an integer parameter.
  - `void cdabs(float);` - Declares a function that takes a float parameter.
  - `void cdabs(double);` - Declares a function that takes a double parameter.

- **Main Function:**
  - Calls the `cdabs` function with the integer argument `3`.

- **Function Definitions:**
  - `cdabs(int x)` is called because the argument `3` is an integer. This function outputs: `3 is an int`.

- **Output:**
  - The program output will be:
    ```
    3 is an int
    ```
  
This illustrates how C++ selects the appropriate function to execute based on the parameter type during a function call. In this case, `cdabs(int x)` is chosen due to the integer argument.
Transcribed Image Text:Sure! Here's a transcription and explanation of the code you provided for an educational website: --- ### Understanding Function Overloading in C++ **Objective:** Determine the output of the following program. ```cpp #include <iostream> using namespace std; void cdabs(int); void cdabs(float); void cdabs(double); int main() { cdabs(3); cin.ignore(); return 0; } void cdabs(int x) { cout << x << " is an int" << endl; } void cdabs(float x) { cout << x << " is a float" << endl; } void cdabs(double x) { cout << x << " is a double" << endl; } ``` **Explanation:** This C++ program demonstrates function overloading—a feature that allows multiple functions with the same name but with different parameter types. - **Function Declarations:** - `void cdabs(int);` - Declares a function that takes an integer parameter. - `void cdabs(float);` - Declares a function that takes a float parameter. - `void cdabs(double);` - Declares a function that takes a double parameter. - **Main Function:** - Calls the `cdabs` function with the integer argument `3`. - **Function Definitions:** - `cdabs(int x)` is called because the argument `3` is an integer. This function outputs: `3 is an int`. - **Output:** - The program output will be: ``` 3 is an int ``` This illustrates how C++ selects the appropriate function to execute based on the parameter type during a function call. In this case, `cdabs(int x)` is chosen due to the integer argument.
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