Determine the name of product(s) for the following reactions (disregard stereochemistry). If there is no reaction, then submit the name of the reactant. 1) LIAIH4 (1 equiv) 2) H3O* 0:

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### Oxidation-Reduction Reaction: Reduction of Ester to Alcohol

**Instruction:**
Determine the name of product(s) for the following reaction (disregard stereochemistry). If there is no reaction, then submit the name of the reactant.

**Reaction Scheme:**

   ![Ester Reduction Reaction](image url)
   
   The given ester structure depicted can be described as an ethyl ester, characterized by an ethyl group attached to an ester functional group (COO).

**Reactants and Conditions:**
1. **Reagent:** LiAlH₄ (Lithium Aluminium Hydride) with 1 equivalent.
2. **Work-up:** H₃O⁺ (Aqueous Acid Work-up)

### Explanation:
In this reaction, the ester is reduced by lithium aluminium hydride (LiAlH₄), which is a strong reducing agent. The ester functional group (COO) is converted to a primary alcohol (CH₂OH) group after the reduction process.

### Detailed Explanation of the Process:
1. **Reduction (Step 1):** LiAlH₄ donates a hydride ion (H⁻) to the carbonyl carbon of the ester group, reducing it to a methoxyl intermediate.
2. **Work-up (Step 2):** The subsequent acidic work-up (H₃O⁺) neutralizes the reaction mixture and fully converts the intermediate into the desired primary alcohols.

### Products:
The reduction of the given ester results in two primary alcohols because the original ester is symmetrical:
- Ethanol (C₂H₅OH)
- Propanol (C₃H₇OH)

### Summary:
The products of the reduction of the ester with lithium aluminium hydride, followed by an acidic work-up, are ethanol and propanol.
Transcribed Image Text:### Oxidation-Reduction Reaction: Reduction of Ester to Alcohol **Instruction:** Determine the name of product(s) for the following reaction (disregard stereochemistry). If there is no reaction, then submit the name of the reactant. **Reaction Scheme:** ![Ester Reduction Reaction](image url) The given ester structure depicted can be described as an ethyl ester, characterized by an ethyl group attached to an ester functional group (COO). **Reactants and Conditions:** 1. **Reagent:** LiAlH₄ (Lithium Aluminium Hydride) with 1 equivalent. 2. **Work-up:** H₃O⁺ (Aqueous Acid Work-up) ### Explanation: In this reaction, the ester is reduced by lithium aluminium hydride (LiAlH₄), which is a strong reducing agent. The ester functional group (COO) is converted to a primary alcohol (CH₂OH) group after the reduction process. ### Detailed Explanation of the Process: 1. **Reduction (Step 1):** LiAlH₄ donates a hydride ion (H⁻) to the carbonyl carbon of the ester group, reducing it to a methoxyl intermediate. 2. **Work-up (Step 2):** The subsequent acidic work-up (H₃O⁺) neutralizes the reaction mixture and fully converts the intermediate into the desired primary alcohols. ### Products: The reduction of the given ester results in two primary alcohols because the original ester is symmetrical: - Ethanol (C₂H₅OH) - Propanol (C₃H₇OH) ### Summary: The products of the reduction of the ester with lithium aluminium hydride, followed by an acidic work-up, are ethanol and propanol.
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