Determine the name of product(s) for the following reactions (disregard stereochemistry). If there is no reaction, then submit the name of the reactant. 1) LIAIH4 (1 equiv) 2) H3O* 0:
Determine the name of product(s) for the following reactions (disregard stereochemistry). If there is no reaction, then submit the name of the reactant. 1) LIAIH4 (1 equiv) 2) H3O* 0:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Oxidation-Reduction Reaction: Reduction of Ester to Alcohol
**Instruction:**
Determine the name of product(s) for the following reaction (disregard stereochemistry). If there is no reaction, then submit the name of the reactant.
**Reaction Scheme:**
![Ester Reduction Reaction](image url)
The given ester structure depicted can be described as an ethyl ester, characterized by an ethyl group attached to an ester functional group (COO).
**Reactants and Conditions:**
1. **Reagent:** LiAlH₄ (Lithium Aluminium Hydride) with 1 equivalent.
2. **Work-up:** H₃O⁺ (Aqueous Acid Work-up)
### Explanation:
In this reaction, the ester is reduced by lithium aluminium hydride (LiAlH₄), which is a strong reducing agent. The ester functional group (COO) is converted to a primary alcohol (CH₂OH) group after the reduction process.
### Detailed Explanation of the Process:
1. **Reduction (Step 1):** LiAlH₄ donates a hydride ion (H⁻) to the carbonyl carbon of the ester group, reducing it to a methoxyl intermediate.
2. **Work-up (Step 2):** The subsequent acidic work-up (H₃O⁺) neutralizes the reaction mixture and fully converts the intermediate into the desired primary alcohols.
### Products:
The reduction of the given ester results in two primary alcohols because the original ester is symmetrical:
- Ethanol (C₂H₅OH)
- Propanol (C₃H₇OH)
### Summary:
The products of the reduction of the ester with lithium aluminium hydride, followed by an acidic work-up, are ethanol and propanol.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Febef2a95-d468-4be7-b2f1-95e4c16dc461%2Fca4f5b13-1314-4d7a-b6c4-9b17aec8f7af%2Fjirzx2n_processed.png&w=3840&q=75)
Transcribed Image Text:### Oxidation-Reduction Reaction: Reduction of Ester to Alcohol
**Instruction:**
Determine the name of product(s) for the following reaction (disregard stereochemistry). If there is no reaction, then submit the name of the reactant.
**Reaction Scheme:**
![Ester Reduction Reaction](image url)
The given ester structure depicted can be described as an ethyl ester, characterized by an ethyl group attached to an ester functional group (COO).
**Reactants and Conditions:**
1. **Reagent:** LiAlH₄ (Lithium Aluminium Hydride) with 1 equivalent.
2. **Work-up:** H₃O⁺ (Aqueous Acid Work-up)
### Explanation:
In this reaction, the ester is reduced by lithium aluminium hydride (LiAlH₄), which is a strong reducing agent. The ester functional group (COO) is converted to a primary alcohol (CH₂OH) group after the reduction process.
### Detailed Explanation of the Process:
1. **Reduction (Step 1):** LiAlH₄ donates a hydride ion (H⁻) to the carbonyl carbon of the ester group, reducing it to a methoxyl intermediate.
2. **Work-up (Step 2):** The subsequent acidic work-up (H₃O⁺) neutralizes the reaction mixture and fully converts the intermediate into the desired primary alcohols.
### Products:
The reduction of the given ester results in two primary alcohols because the original ester is symmetrical:
- Ethanol (C₂H₅OH)
- Propanol (C₃H₇OH)
### Summary:
The products of the reduction of the ester with lithium aluminium hydride, followed by an acidic work-up, are ethanol and propanol.
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