Determine the name of product(s) for the following reactions (disregard stereochemistry). If there is no reaction, then submit the name of the reactant. 1) NaBH4 2) H3O*

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**Determining Products in Organic Reactions: Reduction of a Ketone**

**Problem Statement:**
Determine the name of product(s) for the following reactions (disregard stereochemistry). If there is no reaction, then submit the name of the reactant.

**Reactant Structure:**
The reactant is represented by a chemical structure, specifically a ketone with the formula CH3(CH2)2COCH2CH3.

**Reaction Conditions:**
1) NaBH4 
2) H3O+

**Explanation:**
In this reaction, sodium borohydride (NaBH4) is used as a reducing agent to convert the ketone group (=O) to a hydroxyl group (-OH), forming an alcohol. The presence of H3O+ (acidic conditions, typically a hydronium ion) ensures the final product stabilizes.

**Expected Product:**
The reactant provided is a ketone (pentan-2-one). Under the reaction conditions mentioned:
- Sodium borohydride will reduce the carbonyl group of the ketone.
- The product will be an alcohol.

The name of the product is 2-pentanol.

**Note:**
In practical applications, the stereochemistry (R/S configuration due to chirality) might need consideration. However, for this problem, stereochemistry should be disregarded as instructed.
Transcribed Image Text:**Determining Products in Organic Reactions: Reduction of a Ketone** **Problem Statement:** Determine the name of product(s) for the following reactions (disregard stereochemistry). If there is no reaction, then submit the name of the reactant. **Reactant Structure:** The reactant is represented by a chemical structure, specifically a ketone with the formula CH3(CH2)2COCH2CH3. **Reaction Conditions:** 1) NaBH4 2) H3O+ **Explanation:** In this reaction, sodium borohydride (NaBH4) is used as a reducing agent to convert the ketone group (=O) to a hydroxyl group (-OH), forming an alcohol. The presence of H3O+ (acidic conditions, typically a hydronium ion) ensures the final product stabilizes. **Expected Product:** The reactant provided is a ketone (pentan-2-one). Under the reaction conditions mentioned: - Sodium borohydride will reduce the carbonyl group of the ketone. - The product will be an alcohol. The name of the product is 2-pentanol. **Note:** In practical applications, the stereochemistry (R/S configuration due to chirality) might need consideration. However, for this problem, stereochemistry should be disregarded as instructed.
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