DETERMINE THE LENGTH OF AN EQUIVALENT PIPE OF DIAMETER 20 CM AND FRICTION FACTOR 0.02 FOR A GIVEN PIPE SYSTEM DISCHARGING 0.1 M³/S AND CONSISTING OF (I) A 10 M LINE OF20 CM DIAMETER WITH F= 0.03 (II) WITH THREE 90° BENDS. K = 0.5 FOR EACH, (III) TWO SUDDEN EXPANSIONS; 20-30 CM DIAMETER, (IV) A 15 M LINE OF 30 CM DIAMETER WITH F = 0.025 AND (V) A GLOBE VALVE, FULLY OPEN, ON 30 CM PIPE, K = 10.
DETERMINE THE LENGTH OF AN EQUIVALENT PIPE OF DIAMETER 20 CM AND FRICTION FACTOR 0.02 FOR A GIVEN PIPE SYSTEM DISCHARGING 0.1 M³/S AND CONSISTING OF (I) A 10 M LINE OF20 CM DIAMETER WITH F= 0.03 (II) WITH THREE 90° BENDS. K = 0.5 FOR EACH, (III) TWO SUDDEN EXPANSIONS; 20-30 CM DIAMETER, (IV) A 15 M LINE OF 30 CM DIAMETER WITH F = 0.025 AND (V) A GLOBE VALVE, FULLY OPEN, ON 30 CM PIPE, K = 10.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:DETERMINE THE LENGTH OF AN EQUIVALENT PIPE OF DIAMETER
20 CM AND FRICTION FACTOR 0.02 FOR A GIVEN PIPE SYSTEM
DISCHARGING 0.1 M³/S AND CONSISTING OF
(I) A 10 M LINE OF20 CM DIAMETER WITH F= 0.03
(II) WITH THREE 90° BENDS. K = 0.5 FOR EACH,
(III) TWO SUDDEN EXPANSIONS; 20-30 CM DIAMETER,
(IV) A 15 M LINE OF 30 CM DIAMETER WITH F = 0.025 AND
(V) A GLOBE VALVE, FULLY OPEN, ON 30 CM PIPE, K = 10.
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