Determine how much energy is released when polonium-210 decays according to 21°Po - He + 20°Pb. [Atomic masses: polonium-210 = 209.982857 amu; helium-4 = 4.002603 amu; lead-206 = 205.974449 amu] %3D A. 4.14 x109 kJ/mol B. 7.20 x1011 kJ/mol C. 5.22 x108 kJ/mol 4.66 x109 kJ/mol E. 6.43 x1012 kJ/mol D.
Determine how much energy is released when polonium-210 decays according to 21°Po - He + 20°Pb. [Atomic masses: polonium-210 = 209.982857 amu; helium-4 = 4.002603 amu; lead-206 = 205.974449 amu] %3D A. 4.14 x109 kJ/mol B. 7.20 x1011 kJ/mol C. 5.22 x108 kJ/mol 4.66 x109 kJ/mol E. 6.43 x1012 kJ/mol D.
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Determine how much energy is released when polonium-210 decays according to
21°Po - He + 20°Pb. [Atomic masses: polonium-210 = 209.982857 amu; helium-4 = 4.002603
amu; lead-206 = 205.974449 amu]
4.14 x109 kJ/mol
A.
В.
7.20 x1011 kJ/mol
С.
5.22 x108 kJ/mol
D.
4.66 x109 kJ/mol
E.
6.43 x1012 kJ/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5a965d66-b804-4538-991b-47c3f56e0d65%2Ffda2956a-e8c2-40a0-a742-626f1f40837e%2Fvyevqg_processed.png&w=3840&q=75)
Transcribed Image Text:Question 14 of 17
Determine how much energy is released when polonium-210 decays according to
21°Po - He + 20°Pb. [Atomic masses: polonium-210 = 209.982857 amu; helium-4 = 4.002603
amu; lead-206 = 205.974449 amu]
4.14 x109 kJ/mol
A.
В.
7.20 x1011 kJ/mol
С.
5.22 x108 kJ/mol
D.
4.66 x109 kJ/mol
E.
6.43 x1012 kJ/mol
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