Determine emf of the cell: Fe(s) | Fe(NO3)3 (0.015M) || Zn(NO3)2 (0.025 M) | Zn(s) Standard emf Table: use values you need Fe2+ + 2 e Fe (s) E° = -0.44 V Sn4+ +2 e ----- Sn2+ EO = - 1.50 V Fe+ + e Fe2+ EO = - 0.66 V Fe3+ +3 e Fe(s) EO = - 0.68 V Mn04 + 8 H +5 e Mn2+ + 4 H20 EO = - 1.27 Zn2+ + 2 e Zn (s) EO = - 0.76 V OA. 0.111 V OB. 0.331 V 0.163 V 0.091 V O D. + 0.080 V OE.
Determine emf of the cell: Fe(s) | Fe(NO3)3 (0.015M) || Zn(NO3)2 (0.025 M) | Zn(s) Standard emf Table: use values you need Fe2+ + 2 e Fe (s) E° = -0.44 V Sn4+ +2 e ----- Sn2+ EO = - 1.50 V Fe+ + e Fe2+ EO = - 0.66 V Fe3+ +3 e Fe(s) EO = - 0.68 V Mn04 + 8 H +5 e Mn2+ + 4 H20 EO = - 1.27 Zn2+ + 2 e Zn (s) EO = - 0.76 V OA. 0.111 V OB. 0.331 V 0.163 V 0.091 V O D. + 0.080 V OE.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Determine emf of the cell: Fe(s) | Fe(NO3)3 (0.015M) || Zn(NO3)2 (0.025 M) | Zn(s)
Standard emf Table: use values you need
Fe2+ +2e
Fe (s)
E° = -0.44 V
---- --
Sn4+
+2 e
Sn2+
EO = - 1.50 V
Fe3+
Fe2+
+e -----
EO = - 0.66 V
Fe3+ +3 e
Fe(s)
EO = - 0.68 V
Mn04 + 8 H + 5 e
Mn2+
+ 4 H20
= - 1.27
Zn2+ +
Zn (s)
2 e
EO = - 0.76 V
-0.111 V
OA.
OB. 0.331 V
OC 0.163 V
OD. 0.091 V
+ 0.080 V
OE.
Transcribed Image Text:If 4.0
If 4.0 x 10-8 mol AgNO3 is mixed with 8.0 x 10-6 mol NaBr in 1-L solution,
What will occur? For AgBr Ksp=5.0 x 10"13.
CA AgBr will precipitate because ionic product is greater than solubility product
NaNO3 will precipitate because ionic product is less than solubility product
O B.
oc AgBr will not precipitate because ionic product is greater than solubility product
AgBr AgBr will not precipitate because ionic product is less than solubility product
O D.
NANO3 will precipitate because ionic product is greater than the given Ksp value
E.
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