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Item 19: Question Calculate the voltage of the cell. Ag(s) | AgBr(s), NaBr(aq, 1.0 M)||CdCl₂(aq, 0.050 M)| Cd(s) AgBr(s) + e = Ag(s) + Br |E° = 0.071 V Ag+ + e Ag(s) E° = 0.799 V Cd²+ + 2e Cd(s) | Ksp (AgBr(s)) = 5.0 × 10-13 -0.678 V -0.511 V -0.423 V 0.511 V E° = -0.402 V

Item 19: Question Calculate the voltage of the cell. Ag(s) | AgBr(s), NaBr(aq, 1.0 M)||CdCl₂(aq, 0.050 M)| Cd(s) AgBr(s) + e = Ag(s) + Br |E° = 0.071 V Ag+ + e Ag(s) E° = 0.799 V Cd²+ + 2e Cd(s) | Ksp (AgBr(s)) = 5.0 × 10-13 -0.678 V -0.511 V -0.423 V 0.511 V E° = -0.402 V

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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(For this problem I don't understand what you do with the E of the Ag+ + e- -> Ag(s))

Item 19: Question Calculate the voltage of the cell. Ag(s)|AgBr(s), NaBr(aq, 1.0 M)||CdCl₂(aq, 0.050 M)| Cd(s) AgBr(s) + e = Ag(s) + Br |E° = 0.071 V Ag+ + e Ag(s) E° = 0.799 V cd²+ + 2e Cd(s) | Ksp (AgBr(s)) = 5.0 × 10-13 -0.678 V -0.511 V -0.423 V 0.511 V E° = -0.402 V
Transcribed Image Text:Item 19: Question Calculate the voltage of the cell. Ag(s)|AgBr(s), NaBr(aq, 1.0 M)||CdCl₂(aq, 0.050 M)| Cd(s) AgBr(s) + e = Ag(s) + Br |E° = 0.071 V Ag+ + e Ag(s) E° = 0.799 V cd²+ + 2e Cd(s) | Ksp (AgBr(s)) = 5.0 × 10-13 -0.678 V -0.511 V -0.423 V 0.511 V E° = -0.402 V
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