def display(): print("UTAS") def displayNumber(n1, n2): if n1 > n2: return n1 * n2 else: return n1 - n2 def remarks(number): if number>10: return "SCT"; else: return "HCT"; display() print("Output 1\t:",displayNumber(8,5)) print("Output2\t:",remarks(displayNumber(10,5))) Python 3 def display():print("UTAS")def displayNumber(n1, n2):if n1 > n2:return n1 * n2else:return nl - n2def remarks(number):if number>10:return "SCT";else:return "HCT";display()print("Output 1\t:",displayNumber(8,5))print("Output2\t:",remarks(displayNumber(10,5)))

def display():#this function will return UTAS print("UTAS")def displayNumber(n1,n2):#this…

Answered: def display(): print("UTAS") def…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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def display(): print("UTAS") def displayNumber(n1, n2): if n1 > n2: return n1 * n2 else: return n1 - n2 def remarks(number): if number>10: return "SCT"; else: return "HCT"; display() print("Output 1\t:",displayNumber(8,5)) print("Output2\t:",remarks(displayNumber(10,5))) Python 3

def display():
print("UTAS")
def displayNumber(n1, n2):
if n1 > n2:
return n1 * n2
else:
return nl - n2
def remarks(number):
if number>10:
return "SCT";
else:
return "HCT";
display()
print("Output 1\t:",displayNumber(8,5))
print("Output2\t:",remarks(displayNumber(10,5)))

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