Deduce the structure of a compound with the molecular formula C9H12 that produces the following 'H NMR spectrum: 00 Proton NMR LO 7 6 5 4 Septet 1 Doublet 6 3 2 1 0 Chemical Shift (ppm)
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- Propose a structural formula for the analgesic phenacetin, molecular formula C10H13NO2, based on its 1H-NMR spectrum.The compound whose 1H NMR spectrum is shown has the molecular formula C3H6Br2. Propose a structure.What is the structure of an unknown compound with molecular formula C6H15N that gives the following 1H NMR absorptions: 0.9 (singlet, 1 H), 1.10 (triplet, 3 H), 1.15 (singlet, 9 H), and 2.6 (quartet, 2 H) ppm?
- What is the structure of the compound whose 13C NMR spectrum is shown below?What is the structure of the compound with the formula C8H10O, that shows six signals in its 13C-NMR spectrum, The 1H-NMR spectrum is: 1.98 ppm (1H singlet) 2.82 ppm (2H triplet) 3.80 ppm (2H triplet) 7.22 ppm (5H broad multiplet)Compound A, with molecular formula C4H9Cl, shows two signals in its 13C NMR spectrum. Compound B, an isomer of compound A, shows four signals, and in the proton-coupled mode, the signal farthest downfield is a doublet. Identify compounds A and B
- How many signals will the following compound display in the proton NMR spectrum? Compound: CH3CH2CH2COOCH2CH(CH3)2 O 6 O 7 O 3 O 5 41Compound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively. Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.Determine the structure of the compound C6H100 whose 'H NMR spectrum is shown here. C6H100 6.5 25 7 6 3 1 Chemical shift (ppm)
- Compound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively. Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.How many unique 1H NMR signals are present in the following molecule?Compound A, with molecular formula C4H9Cl, shows two signals in its 13C NMR spectrum. Compound B, an isomer of compound A, shows foursignals, and in the proton-coupled mode, the signal farthest downfield is a doublet. Identify compounds A and B.