Data Table and Results (Part B - Determining Solution Concentration) Measurement Volume of Solution in Evaporating Dish Mass of Evaporating Dish Mass of Evaporating Dish and Solution Mass of Evaporating Dish and Residue For each trial, calculate: 1. Mass of the solution. 1. 839g-60.1369=1.703g 61 4279-60.135g=1.2929 2 Mass of the residue. (0.1859-60.136g=0.049g 60.166g-60.135g=0.031g 4 Molarity of the solution. Trial 1 3 Mass percent of the solution. 1.703g Solute (1.703g+10.00ML) 1.2929 Solute (1.2929+10.00mL) 100-11.447 0.049gNaCl 1mol 0.031gNaci. ImolNaci 58.449 Nac 10.00mL10.00ml 60.136960.135g Kel. 839g 61.4279 60.1859 60.1669 0.01002 Trial 2 58.449 0.01002 Trial 3 -100=14.557. 0.00838m 0.836m Nach = 0.00053mNach 0.053mNach mol L 10.00mol 1L = 0.01 5. Show your calculation for the % error between the molarity you calculated and the true value given to you by your instructor. 10.600-0.053moll 10.836mol-0.6001 100 = 39.33% 0.600 0.600 mol =9.11% Write your unknown sample # and the true value for its molarity in the box below:
Data Table and Results (Part B - Determining Solution Concentration) Measurement Volume of Solution in Evaporating Dish Mass of Evaporating Dish Mass of Evaporating Dish and Solution Mass of Evaporating Dish and Residue For each trial, calculate: 1. Mass of the solution. 1. 839g-60.1369=1.703g 61 4279-60.135g=1.2929 2 Mass of the residue. (0.1859-60.136g=0.049g 60.166g-60.135g=0.031g 4 Molarity of the solution. Trial 1 3 Mass percent of the solution. 1.703g Solute (1.703g+10.00ML) 1.2929 Solute (1.2929+10.00mL) 100-11.447 0.049gNaCl 1mol 0.031gNaci. ImolNaci 58.449 Nac 10.00mL10.00ml 60.136960.135g Kel. 839g 61.4279 60.1859 60.1669 0.01002 Trial 2 58.449 0.01002 Trial 3 -100=14.557. 0.00838m 0.836m Nach = 0.00053mNach 0.053mNach mol L 10.00mol 1L = 0.01 5. Show your calculation for the % error between the molarity you calculated and the true value given to you by your instructor. 10.600-0.053moll 10.836mol-0.6001 100 = 39.33% 0.600 0.600 mol =9.11% Write your unknown sample # and the true value for its molarity in the box below:
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
100%
Help I really have no idea if I calculated it right
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San Diego Miramar College | Chem 152L Laboratory
Data Table and Results (Part B - Determining Solution Concentration)
Measurement
Volume of Solution in Evaporating Dish
Mass of Evaporating Dish
Mass of Evaporating Dish and Solution
Mass of Evaporating Dish and Residue
For each trial, calculate:
1. Mass of the solution. (1.839g-60.136g=1.703g
61 4279-60.135g=1.2929
Trial 1
2 Mass of the residue. (0.1859-60.136g=0.0499
60.166g-60.135g=0.031g
4 Molarity of the solution.
0.031gNaci..
3 Mass percent of the solution. 1.703g Solute
(1.703g+10.00mL)
1.2929 Solute
(1.2929+10.00mL)
10.00-10.00m
60.136960.135g
Kel. 839 61.4279
60.185960.1669
1molNaci
58.449
Trial 2
-100= 14.55 %.
-100-11.447
Nac
0.049gNaCl 1mol 0.00838m6.836m Nach
58.449
0.01002
-0.00053mNaol 0.053mNach mol
0.01002
L
100 = 39.33%
Trial 3
10.00mol 1L
-0.01
5. Show your calculation for the % error between the molarity you calculated and the true value
given to you by your instructor.
10.600-0.053moll
10.836mol-0.6001
0.600
0.600 mol
= 9.11%
Write your unknown sample # and the true value for its molarity in the box below:
Unknown #
Molarity
116
trial 1: erial 2
0.836m 0.053m
... 100"
Transcribed Image Text:128 |
San Diego Miramar College | Chem 152L Laboratory
Data Table and Results (Part B - Determining Solution Concentration)
Measurement
Volume of Solution in Evaporating Dish
Mass of Evaporating Dish
Mass of Evaporating Dish and Solution
Mass of Evaporating Dish and Residue
For each trial, calculate:
1. Mass of the solution. (1.839g-60.136g=1.703g
61 4279-60.135g=1.2929
Trial 1
2 Mass of the residue. (0.1859-60.136g=0.0499
60.166g-60.135g=0.031g
4 Molarity of the solution.
0.031gNaci..
3 Mass percent of the solution. 1.703g Solute
(1.703g+10.00mL)
1.2929 Solute
(1.2929+10.00mL)
10.00-10.00m
60.136960.135g
Kel. 839 61.4279
60.185960.1669
1molNaci
58.449
Trial 2
-100= 14.55 %.
-100-11.447
Nac
0.049gNaCl 1mol 0.00838m6.836m Nach
58.449
0.01002
-0.00053mNaol 0.053mNach mol
0.01002
L
100 = 39.33%
Trial 3
10.00mol 1L
-0.01
5. Show your calculation for the % error between the molarity you calculated and the true value
given to you by your instructor.
10.600-0.053moll
10.836mol-0.6001
0.600
0.600 mol
= 9.11%
Write your unknown sample # and the true value for its molarity in the box below:
Unknown #
Molarity
116
trial 1: erial 2
0.836m 0.053m
... 100
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