Data Report Sheet: Spectrophotometric Determination of an Equilibrium Constant.

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Part A: Determination of a Calibration Curve
Stnd:
[Fe(SCN)2+]
Absorbance
1
0.000000
0.000
0.000090
0.432
3.
4.
0.000106
0.480
0.000127
0.633
5n
0.000189
0.831
6.
0.000204
0.8
Calibration Curve
1.000
0.900
y= 4339.8x + 0.0258
R 0.9904
0.800
0.700
0.600
0.500
0.400
0.300
0.200
0.100
Absorbance
Transcribed Image Text:Part A: Determination of a Calibration Curve Stnd: [Fe(SCN)2+] Absorbance 1 0.000000 0.000 0.000090 0.432 3. 4. 0.000106 0.480 0.000127 0.633 5n 0.000189 0.831 6. 0.000204 0.8 Calibration Curve 1.000 0.900 y= 4339.8x + 0.0258 R 0.9904 0.800 0.700 0.600 0.500 0.400 0.300 0.200 0.100 Absorbance
(ISCN
Data Report Sheet: Spectrophotometric Determination of an Equilibrium
Constant.
Part A: Determination of a Calibration Curve;
Stnd.1
Std. 2
Stnd. 3
Stnd 4
Sind. 5
Stad. 6
(Но)
0.000090
0.000106 0.000127 0.000189 0.000204
(Fe(SCN)"]
Column A
0.432
0.480
0.633
0.831
0.887
Absorbance
Column E
0.
y= 4339.8x + 0.0258
Equafion of Calibration Line:
0.9904
Correlation Coefficient;
4339.8
Slope (br):
Part B: Determination of K
Expt. 1
Еxpt, 2
Expt. 3
Expt. 4
Expt. 5
0,00165
0.00165
0.00165
0.00165
000165
(Table 1)
0.00033
0.00066
0.00099
0.001
0.00165
ISCN at
(Table 1)
0.290
0.524
0.803
1.024
1.199
[Fe(SCN)*l
Column F
|Fe"leqt
148.6799
135.1678
142.2659
141 8466
134.2843
Average K:140 448
I
Transcribed Image Text:(ISCN Data Report Sheet: Spectrophotometric Determination of an Equilibrium Constant. Part A: Determination of a Calibration Curve; Stnd.1 Std. 2 Stnd. 3 Stnd 4 Sind. 5 Stad. 6 (Но) 0.000090 0.000106 0.000127 0.000189 0.000204 (Fe(SCN)"] Column A 0.432 0.480 0.633 0.831 0.887 Absorbance Column E 0. y= 4339.8x + 0.0258 Equafion of Calibration Line: 0.9904 Correlation Coefficient; 4339.8 Slope (br): Part B: Determination of K Expt. 1 Еxpt, 2 Expt. 3 Expt. 4 Expt. 5 0,00165 0.00165 0.00165 0.00165 000165 (Table 1) 0.00033 0.00066 0.00099 0.001 0.00165 ISCN at (Table 1) 0.290 0.524 0.803 1.024 1.199 [Fe(SCN)*l Column F |Fe"leqt 148.6799 135.1678 142.2659 141 8466 134.2843 Average K:140 448 I
Expert Solution
Step 1

Equation obtained from the calibration curve is y = 4339.8x + 0.0258 where

y = Absorbnace

x = [FeSCN2+]

 

Experiment 1

y = 0.290

0.290 = 4339.8x + 0.0258

x = 0.000061

So,

[FeSCN2+]eq = x = 0.000061 M

Now,

Fe3+ + SCN- FeSCN2+

   [Fe3+]  [SCN-]  [FeSCN2+]
 Initial  0.00165  0.00033 0
 Change  -x  -x  +x
 Equillibrium  0.00165-x  0.00033-x  x

So,

[Fe3+]eq = (0.00165-0.000061) = 0.00159 M

[SCN-]eq = 0.000269 M

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