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A solution is prepared at 25 °C that is initially 0.66M in trimethylamine ((CH3)₂N), (K(CH₂), NH). C Calculate the pH of the solution. Round your answer to 2 decimal places. pH = X ,a weak acid with K = 7.4 x 104, and 0.17M in potassium chlorite 5

A solution is prepared at 25 °C that is initially 0.66M in trimethylamine ((CH3)₂N), (K(CH₂), NH). C Calculate the pH of the solution. Round your answer to 2 decimal places. pH = X ,a weak acid with K = 7.4 x 104, and 0.17M in potassium chlorite 5

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Problem Description:** A solution is prepared at 25°C that is initially 0.66 M in trimethylamine \(((CH_3)_3N)\), a weak acid with \(K_b = 7.4 \times 10^{-4}\), and 0.17 M in potassium chlorite \((K(CH_3)NH)\). Calculate the pH of the solution. Round your answer to 2 decimal places. **Instructions:** - Enter your answer in the provided pH input box. - Use the 'Explanation' button for detailed steps if needed. - Click 'Check' to verify your solution.
Transcribed Image Text:**Problem Description:** A solution is prepared at 25°C that is initially 0.66 M in trimethylamine \(((CH_3)_3N)\), a weak acid with \(K_b = 7.4 \times 10^{-4}\), and 0.17 M in potassium chlorite \((K(CH_3)NH)\). Calculate the pH of the solution. Round your answer to 2 decimal places. **Instructions:** - Enter your answer in the provided pH input box. - Use the 'Explanation' button for detailed steps if needed. - Click 'Check' to verify your solution.
Expert Solution
Step 1: Consider the given information:

The concentration of left parenthesis CH subscript 3 right parenthesis subscript 3 straight N = 0.66 M

The concentration of straight K left parenthesis CH subscript 3 right parenthesis subscript 3 NH = 0.17 M

The Kb for left parenthesis CH subscript 3 right parenthesis subscript 3 straight N = 7.4 cross times 10 to the power of negative 4 end exponent

pH of the solution =?      

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