Data from the latest census show that households in Oaktown have 0 to 5 children. Suppose that a household in Oaktown is randomly selected. Let X be the number of children living in that household. Here is the probability distribution of X. 1 2 3 4 s Value x of X P(X=x) 0.19 0.24 0.28 0.16 0.09 0.04 For parts (a) and (b) below, find the probability that the randomly selected household has the number of children described. (a) Greater than 3: | (b) Less than 2:||

A First Course in Probability (10th Edition)
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Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Data from the latest census show that households in Oaktown have 0 to 5 children. Suppose that a household in Oaktown is randomly selected. Let X be the
number of children living in that household. Here is the probability distribution of X.
3 4 s
Value x of X
1
P(X=x)
0.19
0.24
0.28
0.16
0.09
0.04
For parts (a) and (b) below, find the probability that the randomly selected household has the number of children described.
(a) Greater than 3:
(b) Less than 2: ||
Transcribed Image Text:Data from the latest census show that households in Oaktown have 0 to 5 children. Suppose that a household in Oaktown is randomly selected. Let X be the number of children living in that household. Here is the probability distribution of X. 3 4 s Value x of X 1 P(X=x) 0.19 0.24 0.28 0.16 0.09 0.04 For parts (a) and (b) below, find the probability that the randomly selected household has the number of children described. (a) Greater than 3: (b) Less than 2: ||
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