Question 4According to the WHO, the birth weight for male babies born full-term is normally distributed with a mean90.1 oz and a standard deviation of 17.3 oz. Let X be the birth weight of a randomly selected male babyborn full-term.1. Describe the probability distribution of X and state its parameters and σ:XSelect an answerSelect an answerXTBZENa. less than 128.5 oz.b. between 61.9 and 82.1 oz.c. more than 131.7 oz.X²(μ=2. Find the probability that the birth weight of a randomly selected male baby born full-term is3. Find the 65-th percentile for the birth weight.0 =(Round the answer to 4 decimal places)(Round the answer to 4 decimal places)(Round the answer to 4 decimal places)oz (Round the answer to 1 decimal place)

Given that:The birth weight for male babies born full time is normally distributed with a mean of…

Answered: Question 4 According to the WHO, the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The scores of a reference population on the Wechsler Intelligence Scale for children(WISC) are normally distributed with mean 100, and standard deviation 15. If a child is selected at random, find probability that he or she has score between 100 and 120. Select one: O a. 0.4187 O b. 0.5012 O c. 0.618 O d. 0.4082
If z is a standard normal variable, find the probability that z is between -2.07 and 3.28
The average weight of insects for a laboratory experiment is 13.2 g with a standard deviation of 0.8 g. What is the probability of randomly selecting insect weights. A. At most 14 g B. 13.1 g to 13.6 g
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 5. Suppose 100 golfers played the course today. Find the probability that the average score of the 100 golfers exceeded 62. Round to four decimal places. O A. 0.1293 B. 0.3707 O C. 0.4772 O D. 0.0228
The number of ants per acre in the forest is normally distributed with mean 42,000 and standard deviation 12,360. Let X = number of ants in a randomly selected acre of the forest. Round all answers to 4 decimal places where possible.a. Find the probability that a randomly selected acre in the forest has fewer than 39,689 ants. b. Find the probability that a randomly selected acre has between 43,391 and 54,397 ants. c. Find the first quartile. ants (round your answer to a whole number)
The number of ants per acre in the forest is normally distributed with mean 42,000 and standard deviation 12,221. Let X = number of ants in a randomly selected acre of the forest. Round all answers to 4 decimal places where possible. b. Find the probability that a randomly selected acre in the forest has fewer than 32,793 ants. c. Find the probability that a randomly selected acre has between 46,676 and 51,692 ants. d. Find the first quartile. ? ants (round your answer to a whole number) PLEASE ANSWER THE 3 SUBS B, C AND D
The level of nitrogen oxides (NOX) and nonmethane organic gas (NMOG) in the exhaust over the useful life (150,000150,000 miles of driving) of cars of a particular model varies Normally with mean 8080 mg/mi and standard deviation 66 mg/mi. A company has 1616 cars of this model in its fleet. Using Table A, find the level ?L such that the probability that the average NOX + NMOG level ?¯x¯ for the fleet greater than ?L is only 0.030.03 ? (Enter your answer rounded to three decimal places. If you are using CrunchIt, adjust the default precision under Preferences as necessary. See the instructional video on how to adjust precision settings.)
Coal is carried from a mine in west virginia to a power plant in new york in hopper cars on a long train. The automatic hopper car loader is set to put 77 tons of coal into each car. The actual weights of coal loaded into each care are normally distributed with mean u= 77 tons and standard deviation 0= 1.1 ton. A. What is the probability that one car chosen at random will have less than 76.5 tons of coal? ( Round your answer to four decimal places.) B. What is the probability that 29 cars chosen at random will have a mean load weight x of less than 76.5 tons of coal? ( Round your answer to four decimal places) C. Suppose the weight of coal in one car was less than 76.5 tons. Would that fact make you suspect that the loader had slipped out of adjustment. Suppose the weight of coal in 29 cars selected at random had an average x of less than 76.5 tons. Would that fact make you suspect that the loader had slipped out of adjustment? Why?
Given that z is a standard normal random variable, find z for each situation (to 2 decimals). Use Table 1 in Appendix B. a. The area to the left of z is 0.2119. -.8 b. The area between -z and z is 0.903. 1.3 c. The area between -z and z is 0.2206. .28 d. The area to the left of z is 0.9948. 2.59 e. The area to the right of z is 0.6915. -.5
c. Vehicle speeds at a highway location have a normal distribution with mean u = 65 mph and standard deviation o = 5 mph. Find the probability that a randomly selected vehicle speed is greater than 73 mph.
The blood sugar levels of a person follows a normal curve with an average of 4.7mmol/L and a standard deviation of 1.4. In 2014, it is estimated that 8.5% of people around the world have diabetes. For the following questions: 1. Indicate whether the distribution to be used in answering the problem is a normal distribution 2. If yes, solve for the probability a. The probability of getting a random person with a high blood sugar level greater than 7mmol/L. b. The probability of getting a random sample of 150 people with less than 10% having diabetes c. The probability of getting a random sample of 60 people with less than 9% having diabetes d. The probability of getting a random sample of 150 people with a mean blood sugar level less than 5mmol/L. e. The probability of getting a random sample of 25 people with a mean of blood sugar level greater than 4.5mmol/L.
The full height of a certain species of tree has a normal probability distribution with a mean of 195.6 ft and a standard deviation of 7.5 ft. State the random variable. ¯x = the height of a certain species of tree ¯x = the mean height of a certain species of tree x = the height of a certain species of tree x = the diameter of a certain species of tree A tree of this type grows in my backyard, and it stands 187.4 feet tall. Find the probability that the height of a randomly selected tree is shorter than mine. Round to three decimal places.Which is the notation for the probability that the height is shorter than mine? P(x < 187.4) P(¯x < 195.6) P(¯x > 195.6) P(x > 195.6) P(¯x< 187.4) P(x < 195.6)

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