Question A survey asked adults how many different employers they thought they would have during their working lives. Let X represent the number of employers. The table below is a probability distribution table representing the data collected. Find the mean and the standard deviation of the probability distribution using a TI-83, TI-83 Plus, or TI-84 graphing calculator. • Round the mean and the standard deviation to three decimal places. ovide your answer below: mean = standard deviation = X P(x) 0.08505 1 2 0.08538 3 0.08603 4 0.08440 5 0.08342 6 0.08309 7 0.08279 8 0.08211 9 0.08243 10 0.08178 11 0.08178 12 0.08174

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L
A.
OPM Tue Mar 7
3
Question
mean =
13
?
Provide your answer below:
A survey asked adults how many different employers they thought they would have during their working lives. Let X
represent the number of employers. The table below is a probability distribution table representing the data collected. Find
the mean and the standard deviation of the probability distribution using a TI-83, TI-83 Plus, or TI-84 graphing calculator.
• Round the mean and the standard deviation to three decimal places.
knewton.com
standard deviation =
P(x)
1
0.08505
2
0.08538
3
0.08603
4
0.08440
5
0.08342
6
0.08309
7
0.08279
8
0.08211
9
0.08243
10
0.08178
11
0.08178
12 0.08174
38%
X
Transcribed Image Text:L A. OPM Tue Mar 7 3 Question mean = 13 ? Provide your answer below: A survey asked adults how many different employers they thought they would have during their working lives. Let X represent the number of employers. The table below is a probability distribution table representing the data collected. Find the mean and the standard deviation of the probability distribution using a TI-83, TI-83 Plus, or TI-84 graphing calculator. • Round the mean and the standard deviation to three decimal places. knewton.com standard deviation = P(x) 1 0.08505 2 0.08538 3 0.08603 4 0.08440 5 0.08342 6 0.08309 7 0.08279 8 0.08211 9 0.08243 10 0.08178 11 0.08178 12 0.08174 38% X
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