A bus comes by every 14 minutes. The times from when a person arives at the busstop until the bus arrives follows a Uniform distribution from 0 to 14 minutes. A person arrives at the bus stop at a randomly selected time. Round to 4 decimal places where possible. a. The mean of this distribution is c. The probability that the person will wait more than 6 minutes is d. Suppose that the person has already been waiting for 1 minutes. Find the probability that the person's total waiting time will be between 4.7 and 8.3 minutes e. 55% of all customers wait at least how long for the train? minutes. b. The standard deviation is
A bus comes by every 14 minutes. The times from when a person arives at the busstop until the bus arrives follows a Uniform distribution from 0 to 14 minutes. A person arrives at the bus stop at a randomly selected time. Round to 4 decimal places where possible. a. The mean of this distribution is c. The probability that the person will wait more than 6 minutes is d. Suppose that the person has already been waiting for 1 minutes. Find the probability that the person's total waiting time will be between 4.7 and 8.3 minutes e. 55% of all customers wait at least how long for the train? minutes. b. The standard deviation is
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Transcribed Image Text:A bus comes by every 14 minutes. The times from when a person arives at the busstop until the bus arrives
follows a Uniform distribution from 0 to 14 minutes. A person arrives at the bus stop at a randomly selected
time. Round to 4 decimal places where possible.
a. The mean of this distribution is
c. The probability that
the person will wait more than 6 minutes is
d. Suppose that the person has already been waiting for
1 minutes. Find the probability that the person's total waiting time will be between 4.7 and 8.3 minutes
e. 55% of all customers wait at least how long for the train?
minutes.
Suppose that the weight of an newborn fawn is Uniformly distributed between 1.9 and 4 kg. Suppose that a
newborn fawn is randomly selected. Round answers to 4 decimal places when possible.
a. The mean of this distribution is
fawn will weigh exactly 3.6 kg is P(x-3.6)=
weigh between 2 and 3 is P(2<x<3)=
than 2.62 is P(x> 2.62) =
20
83
b. The standard deviation is
Complete the following probability distribution table for the discrete random yariable X:
Probability Distribution Table
X
-2
5
P(X)
0.5
b. The standard deviation is
c. The probability that i
d. The probability that a newborn fawn will be
e. The probability that a newborn fawn will be weigh more
f. P(x > 2.6 x <3.4) -
Find the 26th percentile.
8
0.2
0.2
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