d. What type of inhibition is exhibited against NAD* as a cofactor? Describe what is going on in this type of inhibition. e. Referring to the mechanism below, what step is pyrazole likely interfering with given your answers in c and d? 1. binding of NAD+ to the enzyme, LADH 2. binding of C₂H5OH to LADH 3. Oxidation of C₂H5OH (This is the reaction step) and product dissociation 4. Dissociation of NADH from LADH NAD+ + LADH NAD LADH + NAD C₂H5OH LADH C₂H5OH NADH LADH + NAD LADH k₂ k + NAD LADH C₂H5OH NADH LADH + NADH+ LADH CH3CHO+H*
d. What type of inhibition is exhibited against NAD* as a cofactor? Describe what is going on in this type of inhibition. e. Referring to the mechanism below, what step is pyrazole likely interfering with given your answers in c and d? 1. binding of NAD+ to the enzyme, LADH 2. binding of C₂H5OH to LADH 3. Oxidation of C₂H5OH (This is the reaction step) and product dissociation 4. Dissociation of NADH from LADH NAD+ + LADH NAD LADH + NAD C₂H5OH LADH C₂H5OH NADH LADH + NAD LADH k₂ k + NAD LADH C₂H5OH NADH LADH + NADH+ LADH CH3CHO+H*
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
Related questions
Question
Answer for D, and E. The answers for A, B, and C are down below.
![**Pyrazole as a Non-toxic Inhibitor of LADH-Catalyzed Ethanol Oxidation**
Pyrazole has been proposed as a possible non-toxic inhibitor of liver alcohol dehydrogenase (LADH)-catalyzed ethanol oxidation. Kinetic experiments were conducted to study the velocity of the reaction with and without pyrazole, based on varying concentrations of ethanol \([C_2H_5OH]\) and nicotinamide adenine dinucleotide \([NAD^+]\).
**Table 1: Effect of \([C_2H_5OH]\) on Reaction Velocity**
- **\[C_2H_5OH\] M**:
- 0.008
- 0.002
- 0.001
- 0.00067
- **\[Vo (relative units) No pyrazole\]**:
- 2.1
- 1.8
- 1.5
- 1.35
- **\[Vo (relative units) 1x10^-5 M pyrazole\]**:
- 1.7
- 1.0
- 0.69
- 0.52
**Table 2: Effect of \([NAD^+]\) on Reaction Velocity**
- **\[NAD^+\]**:
- 0.00011
- 0.000056
- 0.000033
- 0.000017
- **\[Vo (relative units) No pyrazole\]**:
- 1.7
- 1.4
- 1.3
- 0.95
- **\[Vo (relative units) 4x10^-5 M pyrazole\]**:
- 0.85
- 0.71
- 0.63
- 0.47
**Tasks:**
a. Plot the data as Lineweaver-Burke plots on two separate graphs.
b. Determine the Km values for \([C_2H_5OH]\) and \([NAD^+]\). (Vmax cannot be determined due to lack of exact velocity units.)
c. Describe the type of inhibition exhibited by pyraz](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2705ec0-2034-4d28-a385-06c28bb62d2f%2F017e1983-11c6-46c7-ab0d-29d67e34de55%2Fynym9x5_processed.png&w=3840&q=75)
Transcribed Image Text:**Pyrazole as a Non-toxic Inhibitor of LADH-Catalyzed Ethanol Oxidation**
Pyrazole has been proposed as a possible non-toxic inhibitor of liver alcohol dehydrogenase (LADH)-catalyzed ethanol oxidation. Kinetic experiments were conducted to study the velocity of the reaction with and without pyrazole, based on varying concentrations of ethanol \([C_2H_5OH]\) and nicotinamide adenine dinucleotide \([NAD^+]\).
**Table 1: Effect of \([C_2H_5OH]\) on Reaction Velocity**
- **\[C_2H_5OH\] M**:
- 0.008
- 0.002
- 0.001
- 0.00067
- **\[Vo (relative units) No pyrazole\]**:
- 2.1
- 1.8
- 1.5
- 1.35
- **\[Vo (relative units) 1x10^-5 M pyrazole\]**:
- 1.7
- 1.0
- 0.69
- 0.52
**Table 2: Effect of \([NAD^+]\) on Reaction Velocity**
- **\[NAD^+\]**:
- 0.00011
- 0.000056
- 0.000033
- 0.000017
- **\[Vo (relative units) No pyrazole\]**:
- 1.7
- 1.4
- 1.3
- 0.95
- **\[Vo (relative units) 4x10^-5 M pyrazole\]**:
- 0.85
- 0.71
- 0.63
- 0.47
**Tasks:**
a. Plot the data as Lineweaver-Burke plots on two separate graphs.
b. Determine the Km values for \([C_2H_5OH]\) and \([NAD^+]\). (Vmax cannot be determined due to lack of exact velocity units.)
c. Describe the type of inhibition exhibited by pyraz
![### Step 1
Since you have posted a question with multiple sub-parts, we will provide the solution only to the first three sub-parts as per our Q&A guidelines. Please repost the remaining sub-parts separately.
---
### Step 2
#### 3. (a) Lineweaver-Burk Plot for \( C_2H_5OH \) in Presence and Absence of Inhibitor:
**Data Table:**
| \([S]\) | \(V_0\) (no inhibitor) | \(V_0\) (with inhibitor) | \(1/[S]\) | \(1/V_0\) (no inhibitor) | \(1/V_0\) (with inhibitor) |
|---------|-----------------------|--------------------------|-----------|--------------------------|---------------------------|
| 0.008 | 2.1 | 1.7 | 125 | 0.476190476 | 0.588235294 |
| 0.002 | 1.8 | 1.5 | 500 | 0.555555556 | 0.666666667 |
| 0.00067 | 1.35 | 0.52 | 1492.537313 | 0.740740741 | 1.923076923 |
**Graph Description:**
The graph plots the reciprocal of the initial velocity (\(1/V_0\)) against the reciprocal of substrate concentration (\(1/[S]\)). The plot includes two lines: one for velocities without inhibitor and one with inhibitor. It shows that the presence of an inhibitor affects the enzyme kinetics by altering the slope and intercept of the plot.
#### Lineweaver-Burk Plot for \( NAD^+ \) in Presence and Absence of Inhibitor:
**Data Table:**
| \([S]\) | \(V_0\) (no inhibitor) | \(V_0\) (with inhibitor) | \(1/[S]\) | \(1/V_0\) (no inhibitor) | \(1/V_0\) (with inhibitor) |
|----------|-----------------------|--------------------------|-----------|--------------------------|---------------------------|
| 0.005 | 1.9 | 0.85 | 200 | 0.526315789 |](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd2705ec0-2034-4d28-a385-06c28bb62d2f%2F017e1983-11c6-46c7-ab0d-29d67e34de55%2F4l65ps2_processed.png&w=3840&q=75)
Transcribed Image Text:### Step 1
Since you have posted a question with multiple sub-parts, we will provide the solution only to the first three sub-parts as per our Q&A guidelines. Please repost the remaining sub-parts separately.
---
### Step 2
#### 3. (a) Lineweaver-Burk Plot for \( C_2H_5OH \) in Presence and Absence of Inhibitor:
**Data Table:**
| \([S]\) | \(V_0\) (no inhibitor) | \(V_0\) (with inhibitor) | \(1/[S]\) | \(1/V_0\) (no inhibitor) | \(1/V_0\) (with inhibitor) |
|---------|-----------------------|--------------------------|-----------|--------------------------|---------------------------|
| 0.008 | 2.1 | 1.7 | 125 | 0.476190476 | 0.588235294 |
| 0.002 | 1.8 | 1.5 | 500 | 0.555555556 | 0.666666667 |
| 0.00067 | 1.35 | 0.52 | 1492.537313 | 0.740740741 | 1.923076923 |
**Graph Description:**
The graph plots the reciprocal of the initial velocity (\(1/V_0\)) against the reciprocal of substrate concentration (\(1/[S]\)). The plot includes two lines: one for velocities without inhibitor and one with inhibitor. It shows that the presence of an inhibitor affects the enzyme kinetics by altering the slope and intercept of the plot.
#### Lineweaver-Burk Plot for \( NAD^+ \) in Presence and Absence of Inhibitor:
**Data Table:**
| \([S]\) | \(V_0\) (no inhibitor) | \(V_0\) (with inhibitor) | \(1/[S]\) | \(1/V_0\) (no inhibitor) | \(1/V_0\) (with inhibitor) |
|----------|-----------------------|--------------------------|-----------|--------------------------|---------------------------|
| 0.005 | 1.9 | 0.85 | 200 | 0.526315789 |
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