d = 10[ 5 1,663785 × 10-3 × Q1,85 x Lt ΔΡ ΧΡ Where: d is the diameter of the pipe; Q is the flow rate in the area AP is the permissible pressure loss P is the work pressure considered Lt is the total length in the area

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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Q 122.

Describe the methodology for a project report of a compressed air system for a plating workshop, in which two sanders, two spray guns (used in the painting area) and two polishing machines (used in the polishing area) are not used.

The total flow rate of the system, which will be used to size the compressor, is the sum of the flow rates required by these pneumatic tools described above.

The permissible pressure loss of the system was considered to be 0.3 bar and the working pressure of the system was considered to be 6 bar.

The total length of the pipe in each area is calculated by adding the linear length of the pipe to the equivalent length of the accidents.

The slope of the pipe was adopted as 2%, with the objective of condensate drainage

With this data, the diameter of the pipe in each area of the workshop is calculated using the attached formula

d = 10[
5 1,663785 × 10-3 × Q1,85 x Lt
ΔΡ ΧΡ
Where:
d is the diameter of the pipe;
Q is the flow rate in the area
AP is the permissible pressure loss
P is the work pressure considered
Lt is the total length in the area
Transcribed Image Text:d = 10[ 5 1,663785 × 10-3 × Q1,85 x Lt ΔΡ ΧΡ Where: d is the diameter of the pipe; Q is the flow rate in the area AP is the permissible pressure loss P is the work pressure considered Lt is the total length in the area
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