Current Attempt in Progress A hollow aluminum rod (1) is connected to a hollow bronze rod (2) at flange B, as shown below. Aluminum rod (1) has an area of A1 = 450 mm?, a length of L1 = 2200 mm, and an elastic modulus of E = 70 GPa. Bronze rod (2) has an area of A2 = 225 mm?, a length of L2 = 5060 mm, and an elastic modulus of E2 = 100 GPa. The normal stress in aluminum rod (1) must be limited to 221 MPa, and the normal stress in bronze rod (2) must be limited to 170 MPa. Determine the maximum downward load P that may be applied at flange B. (2) L2 В L1 (1) Pmax - i kN

Current Attempt in Progress A hollow aluminum rod (1) is connected to a hollow bronze rod (2) at flange B, as shown below. Aluminum rod (1) has an area of A1 = 450 mm?, a length of L1 = 2200 mm, and an elastic modulus of E = 70 GPa. Bronze rod (2) has an area of A2 = 225 mm?, a length of L2 = 5060 mm, and an elastic modulus of E2 = 100 GPa. The normal stress in aluminum rod (1) must be limited to 221 MPa, and the normal stress in bronze rod (2) must be limited to 170 MPa. Determine the maximum downward load P that may be applied at flange B. (2) L2 В L1 (1) Pmax - i kN

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The assembly is composed of a steel shell and an aluminum core that has been welded to a rigid plate. The gap between the plate and the aluminum is initially 1- mm. If the assembly's temperature is reduced by 180°C, determine (a) the final axial stresses in each material and (b) the deflection of the rigid bar. To support your response, draw a deformation diagram with appropriate labels. Use the following properties: Aluminum core Steel shell Diameters (mm) d = 15 mm do = 30 mm d₁ = 20 mm E (GPa) 70 200 2 m a (/°C) 22 x 10-6 12 x 10-6
Normal stress is calculated dividing the reaction by the cross-sectional area. Is this approach valid for any point of a structural member? Why or why not? To answer this question, consider the loading point, cross- sectional shape, etc.
Current Attempt in Progress A polymer cylinder (2) is clamped between rigid heads by two steel bolts (1). The steel [E = 29,000 ksi; a = 6.5x10-6/F] bolts have a diameter of 0.35 in. The polymer [E = 370 ksi; a = 37.2x 10-/°F] cylinder has an outside diameter of 6.9 in. and a wall thickness of 0.65 in. Assume a = 28 in. and b = 34 in. If the temperature of this assembly changes by AT = 130°F, determine: (a) the normal stress in the polymer cylinder. (b) the normal strain in the polymer cylinder. (c) the normal strain in the steel bolts. (1) (2) (1) b. Answer: (a) 02 = psi. (b) €2 = (c) E1 = Save for Later Attempts: 0 of 1 used Submit Answer NWP Assessme. NWP Assessme. O ManyCam Desktop 30°C
A polymer cylinder (2) is clamped between rigid heads by two steel bolts (1). The steel [E = 29,000 ksi; a = 6.5x10-6/°F] bolts have a diameter of 0.30 in. The polymer [E = 370 ksi; a = 38.3x 10-6/°F] cylinder has an outside diameter of 6.6 in. and a wall thickness of 0.75 in. Assume a = 29 in. and b = 37 in. If the temperature of this assembly changes by AT = 135°F, determine: (a) the normal stress in the polymer cylinder. (b) the normal strain in the polymer cylinder. (c) the normal strain in the steel bolts. %3D %3D %3D %3D (1) C (2) a (1) b. Answer: (a) 02 = psi. (b) E2 = 3d (c) E1 =
Normal stress is calculated dividing the reaction by the cross-sectional area. Is this approach valid for any point of a structural member? Why or why not? To answer this question, consider the loading point, cross- sectional shape, etc.
A fillet-welded joint is shown in the figure. The size of the weld is 8 mm. Safe stress in the weld is 110 N/mm². What is the safe force (to the nearest magnitude) to which the weld can be subjected? 80 mm 60 mm
Normal stress is calculated dividing the reaction by the cross-sectional area. Is this approach valid for any point of a structural member? Why or why not? To answer this question, consider the loading point, cross- sectional shape, etc.
At a temperature of 29.8 °C a 0.4-mm gap exists between the ends of the rods shown. At a later time when the temperature has reached 133.3°C, determine the change in length of the steel rod if L = 312.45 mm and M=201 mm. Round off the final answer to four decimal places. d - L M - B Aluminum A = 2000 mm² E = 75 GPa a = 23 x 10-6/°C Stainless steel A = 800 mm² E = 190 GPa α = 17.3 x 10-6/°C
A mild steel flat of width 120 mm and thickness 10 mm is bent into an arc of a circle of radius 10 m by applying a pure moment 'M'. If E is 200 GPa, then magnitude of the pure moment 'M' will be
Engineering Mechanics. please help to provide solution for the this problem.
Solve it