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- The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…A consecutive sequence a list of numbers that are organized in increasing order with the next eleme. one bigger than the current. Write a non-recursive method "lengthConsec", which takes an IntNode myList as the parameter and returns the length of the consecutive sequence in myList. To simplify the implementation, you can assume that there is no more than one consecutive sequence in the list. For example, in the following linked list, the consecutive sequence begins at node "5" and ends at node "7", so lengthConsec (myList) should return 3 in this case. myList 8 13 4 public class IntNode { 12 private int m_data; private IntNode m_link; Consecutive sequence 6 7 28Write a recursive Python function named initList to create a list containing the values from 0 to n-1. • The function takes two parameters, a reference to the list and an integer which is the value n. In the main program you must: - initialize a list (L = []) - call the recursive function initList with this list L, to modify it - and, ask the user to enter the value n from the keyboard
- Construct recursive versions of the library functions that: a. calculate the "sum" of a list of numbers. b. "take" a given number of elements from the beginning of a list. c. select the "last" element of a non-empty list .Write a program as follows. Follow instructions carefully to avoid point deductions. All statements should be in the main function: create an empty list named nums. use a loop to add 20 random integers, all in the range from 1-100, to nums. print the total of all list elements. print the highest number in the list. print the lowest number in the list. sort the list and then reverse it. use another loop to display the sorted numbers in descending order, all on the same line, separated by a single space. determine if 75 is in the list. If it is, report the index of its first occurrence. If it is absent from the list, indicate that, too. make a new list named middle_10 by slicing out the middle 10 elements of the descending list. Use a loop to display the elements in middle_10 all on one line. make an empty list named evens and another empty list named odds. use a loop to process nums, adding even elements and odd elements to their respective lists. print both evens and odds. Crude dumps…I need the code from start to end with no errors and the explanation for the code ObjectivesJava refresher (including file I/O)Use recursionDescriptionFor this project, you get to write a maze solver. A maze is a two dimensional array of chars. Walls are represented as '#'s and ' ' are empty squares. The maze entrance is always in the first row, second column (and will always be an empty square). There will be zero or more exits along the outside perimeter. To be considered an exit, it must be reachable from the entrance. The entrance is not an exit.Here are some example mazes:mazeA7 9# # ###### # # ## # # #### # ## ##### ## ########## RequirementsWrite a MazeSolver class in Java. This program needs to prompt the user for a maze filename and then explore the maze. Display how many exits were found and the positions (not indices) of the valid exits. Your program can display the valid exits found in any order. See the examples below for exact output requirements. Also, record…
- python 3 Write a program that lists all ways people can line up for a photo (all permutations of a list of strings). The program will read a list of one word names, then use a recursive method to create and output all possible orderings of those names, one ordering per line. When the input is: Julia Lucas Mia then the output is (must match the below ordering): Julia Lucas Mia Julia Mia Lucas Lucas Julia Mia Lucas Mia Julia Mia Julia Lucas Mia Lucas Julia question: is it any way that i can use ('if' statement as base case, and 'else' statement as recursive case) in the code below? thanks. code: def all_permutations(permList, nameList):# TODO: Implement method to create and output all permutations of the list of names.def createPermutationsList(nameList):f = len(nameList) if f == 0:return [] if f == 1:return [nameList] permList = [] for i in range(f):newList = nameList[i]remaining = nameList[:i] + nameList[i+1:]for p in createPermutationsList(remaining):permList.append([newList] + p)…Complete the recursive function remove_last which creates a new list identical to the input list s but with the last element in the sequence that is equal to x removed. Hint: Remember that you can use negative indexing on lists! For example 1st [-1] refers to the last element in a list 1st, lst [-2] refers to the second to last element... def remove_last(x, s): """Create a new list that is identical to s but with the last element from the list that is equal to x removed. >>> remove_last(1, []) [] >>> remove_last(1, [1]) [] >>> [1] >>> [2] remove_last(1, [1,1]) remove_last(1, [2,1]) >>> remove_last(1, [3,1,2]) [3, 2] >>> remove_last(1, [3,1,2,1]) [3, 1, 2] >>> remove_last (5, [3, 5, 2, 5, 11]) [3, 5, 2, 11] IIIII "*** YOUR CODE HERE ***" Illustrated here is a more complete doctest that shows good testing methodology. It is a little cumbersome as documentation, but you'll want to think about it for your projects. Test every condition that might come up. Then you won't be surprised when…Given a list of integers, you want to know whether it is possible to divide the integers into two sets, so that the sums of the two sets are the same. Every integer must be in one set or the other. Write a recursive helper method that takes any number of arguments you like, and make the initial call to your recursive helper method from equalSum(). Do not use any loops or regular expressions. Test case 1: equalSum([2, 3, 5]) true Test case 2: equalSum([2, 2, 5]) false
- A sequential search of a sorted list can halt when the target is less than a given element in the list. Modify the program to stop when the target becomes less than the current value being compared. In a sorted list, this would indicate that the target is not in the list and searching the remaining values is unnecessary. ----------------------------------------------------------------------------------- """ File: search.py Project 11.1 """ def sequentialSearch(target, lyst): """Returns the position of the target item if found, or -1 otherwise. The lyst is assumed to be sorted in ascending order.""" position = 0 while position < len(lyst): if target == lyst[position]: return position position += 1 return -1 def main(): """Tests with three lists.""" print(sequentialSearch(3, [0, 1, 2, 3, 4])) print(sequentialSearch(3, [0, 1, 2])) # Should stop at second position. print(sequentialSearch(3, [0, 4, 5, 6])) if…do these coe in python: Suppose you have the following animal names in a list: cat, dog,mouse, hamster. Write a code that prints the first letter, the last letter, andthe length of each animal’s name. Print out all the animal names that havea length greater than 3. after that Write a program that counts the number of aletter that appears in the list (i.e. the frequency of the letter).
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