Create a Benesi-Hildebrand Plot. To do this, plot the data of 1/(F-F0) (y-axis) vs.1/[CD]0 (x-axis). Fit the data to [Egn 8]. The fitting parameters of the data to astraight-line equation (y = mx + b) should allow you to calculate Ka. Take carewith units, concentrations will need to be M when reporting the Ka value.X ul of ME-b-CD(20mM)[ME-b-CD]ul of ANSY ul ofFluorescence(mM)(0.4mM)PBS[CD] mMintensityF- FO50015000.3710050014009.4269.05622005001300216.7616.393.30050012003.22.62122.2514005001100427.49627.126500500100030.57330.2036.60050090034.34433.9747700500800736.99136.6218.8005007008.38.47838.1089.9005006009.41.01240.6421010005005001043.76943.3991212005003001245.6445.271414005001001447.5247.151515005001548.35947.989

Answered: Image /qna-images/answer/5b9db3e7-aee4-419c-ba15-577c1c3bed94.jpg

Create a Benesi-Hildebrand Plot. To do this, plot the data of 1/(F-F0) (y-axis) vs. 1/[CD]O (x-axis). Fit the data to [Egn 8]. The fitting parameters of the data to a straight-line equation (y = mx + b) should allow you to calculate Ka. Take care with units, concentrations will need to be M when reporting the Ka value. X ul of ME-b-CD (20mM) [ME-b-CD] ul of ANS Y ul of Fluorescence (mM) (0.4mM) F- FO PBS [CD] mM intensity 500 1500 0.37 1 100 500 1400 1 9.426 9.056 200 500 1300 2 16.76 16.39 3. 300 500 1200 3. 22.621 22.251 400 500 1100 27.496 27.126 500 500 1000 30.573 30.203 6. 600 500 900 34.344 33.974 7 700 500 800 7 36.991 36.621 8. 800 500 700 8. 38.478 38.108 900 500 600 9. 41.012 40.642 10 1000 500 500 10 43.769 43.399 12 1200 500 300 12 45.64 45.27 14 1400 500 100 14 47.52 47.15 15 1500 500 15 48.359 47.989

Create a Benesi-Hildebrand Plot. To do this, plot the data of 1/(F-F0) (y-axis) vs. 1/[CD]O (x-axis). Fit the data to [Egn 8]. The fitting parameters of the data to a straight-line equation (y = mx + b) should allow you to calculate Ka. Take care with units, concentrations will need to be M when reporting the Ka value. X ul of ME-b-CD (20mM) [ME-b-CD] ul of ANS Y ul of Fluorescence (mM) (0.4mM) F- FO PBS [CD] mM intensity 500 1500 0.37 1 100 500 1400 1 9.426 9.056 200 500 1300 2 16.76 16.39 3. 300 500 1200 3. 22.621 22.251 400 500 1100 27.496 27.126 500 500 1000 30.573 30.203 6. 600 500 900 34.344 33.974 7 700 500 800 7 36.991 36.621 8. 800 500 700 8. 38.478 38.108 900 500 600 9. 41.012 40.642 10 1000 500 500 10 43.769 43.399 12 1200 500 300 12 45.64 45.27 14 1400 500 100 14 47.52 47.15 15 1500 500 15 48.359 47.989

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

(e) Sketch the ¹H NMR spectrum of benzoylferrocene I. Indicate the chemical shift range of the ¹H NMR signals and their relatively intensity (integration) and assign the signals. O=C Fe (f) Give a reaction sequence that can be employed for the synthesis of titanium complex J. Start from TiCl4. Cp₂Ti J Me -Me
IR Spectrum U= . IR=? NAR Spectrum 6. a THS
What is the molar extinction coefficient at 625 nm for this copper (II) acetate solution? How was it determined? Standard Solution Concentration (M) Absorbance 1 0.025 0.049 2 0.050 0.153 3 0.100 0.242 4 0.200 0.499 5 0.250 0.694
See the attached photo
In general, we want to have absorptions less than or equal to 1. Given that an ethanol solution of compound Y (150.0 g/mol) in a 1.00 cm quartz cell has an extinction coefficient (E) of 23,150 at Amax=235 nm, what is the top concentration, in uM, we should consider for compound Y? Report your answer to the correct number of significant figures.
6. The UV-Vis absorption spectrum was measured for three different concentrations (10 mM, 20 mM, and 30 mM) of an analyte that we will call orangium as shown in the figure below. A 1.000 cm cuvette is used for all of the experiments. 1.00 0.90 0.80 0.70 0.60 a 0.50
UV: max 235 (ε 12,000) and max 314 (ε 120) EIMS: m/z 39 (31%), 41 (33%), 55 (37%), 69 (26%), 98 (100%), 99 (7%), 100 (0.2%) IR: Imm IR spectrum in CCl4 solvent 2950 cm-¹ 2000 4) RC=N 5) 0-H BAYEHUNIERI - R 1630 cm-¹ 1710 cm-¹ $10 4a) Which of the following heteroatoms that are definitely NOT present based on the EIMS data? (Circle all that apply). Br Cl FSI 0 4 continued) Please refer to data on preceding page. 4b) From the EIMS data what is the best estimate of the number of carbon atoms in this molecule? 4c) From the UV data, conjugated л-bonds are: definitely present definitely absent 4d) From the IR spectrum alone, which of the following functional groups can be definitely ruled OUT? Circle those that are ruled out and briefly explain why. 1) C=0 2) RC=CR 3) C=C cannot tell
Can you explain the IR spectrum ?