Create a Benesi-Hildebrand Plot. To do this, plot the data of 1/(F-F0) (y-axis) vs.1/[CD]0 (x-axis). Fit the data to [Egn 8]. The fitting parameters of the data to astraight-line equation (y = mx + b) should allow you to calculate Ka. Take carewith units, concentrations will need to be M when reporting the Ka value.X ul of ME-b-CD(20mM)[ME-b-CD]ul of ANSY ul ofFluorescence(mM)(0.4mM)PBS[CD] mMintensityF- FO50015000.3710050014009.4269.05622005001300216.7616.393.30050012003.22.62122.2514005001100427.49627.126500500100030.57330.2036.60050090034.34433.9747700500800736.99136.6218.8005007008.38.47838.1089.9005006009.41.01240.6421010005005001043.76943.3991212005003001245.6445.271414005001001447.5247.151515005001548.35947.989

Answered: Image /qna-images/answer/5b9db3e7-aee4-419c-ba15-577c1c3bed94.jpg

Create a Benesi-Hildebrand Plot. To do this, plot the data of 1/(F-F0) (y-axis) vs. 1/[CD]O (x-axis). Fit the data to [Egn 8]. The fitting parameters of the data to a straight-line equation (y = mx + b) should allow you to calculate Ka. Take care with units, concentrations will need to be M when reporting the Ka value. X ul of ME-b-CD (20mM) [ME-b-CD] ul of ANS Y ul of Fluorescence (mM) (0.4mM) F- FO PBS [CD] mM intensity 500 1500 0.37 1 100 500 1400 1 9.426 9.056 200 500 1300 2 16.76 16.39 3. 300 500 1200 3. 22.621 22.251 400 500 1100 27.496 27.126 500 500 1000 30.573 30.203 6. 600 500 900 34.344 33.974 7 700 500 800 7 36.991 36.621 8. 800 500 700 8. 38.478 38.108 900 500 600 9. 41.012 40.642 10 1000 500 500 10 43.769 43.399 12 1200 500 300 12 45.64 45.27 14 1400 500 100 14 47.52 47.15 15 1500 500 15 48.359 47.989

Create a Benesi-Hildebrand Plot. To do this, plot the data of 1/(F-F0) (y-axis) vs. 1/[CD]O (x-axis). Fit the data to [Egn 8]. The fitting parameters of the data to a straight-line equation (y = mx + b) should allow you to calculate Ka. Take care with units, concentrations will need to be M when reporting the Ka value. X ul of ME-b-CD (20mM) [ME-b-CD] ul of ANS Y ul of Fluorescence (mM) (0.4mM) F- FO PBS [CD] mM intensity 500 1500 0.37 1 100 500 1400 1 9.426 9.056 200 500 1300 2 16.76 16.39 3. 300 500 1200 3. 22.621 22.251 400 500 1100 27.496 27.126 500 500 1000 30.573 30.203 6. 600 500 900 34.344 33.974 7 700 500 800 7 36.991 36.621 8. 800 500 700 8. 38.478 38.108 900 500 600 9. 41.012 40.642 10 1000 500 500 10 43.769 43.399 12 1200 500 300 12 45.64 45.27 14 1400 500 100 14 47.52 47.15 15 1500 500 15 48.359 47.989

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

These are low energy electrons (-10-50 eV) generated from the collision * between the incoming electrons and the loosely bonded outer electrons. Secondary electrons Auger electrons Backscatterred electrons Ejected electrons X-rays photons Provides quantitative, elemental, chemical state and functional group information from the surface of materials, detecting all elements except H and He. AFM SEM XPS XRD SIMS It is a solid surface on which the stationary phase is bound or coated. * mobile phase column supporting medium stationary phase
(e) Sketch the ¹H NMR spectrum of benzoylferrocene I. Indicate the chemical shift range of the ¹H NMR signals and their relatively intensity (integration) and assign the signals. O=C Fe (f) Give a reaction sequence that can be employed for the synthesis of titanium complex J. Start from TiCl4. Cp₂Ti J Me -Me
One common way to determine phosphorus is by mixing 12-molybdophosphate complex with ascorbic acid to give an intense blue-colored species called molybdenum blue. The absorbance of molybdenum blue can be measured at 650 nm. A calibration graph was constructed as follow. Deduce the analytical technique used and calculate the concentration of unknown water samples analyzed which demonstrated absorbance reading of 0.269 (sample 1), 0.532 (sample 2) and 0.478 (sample 3). P calibration curve 0.8 0.6 0.4 y = 0.218x + 0.004 R2 = 0.9996 0.2 0.5 1 1.5 2 2.5 3 3.5 Concentration (ppm) Absorbance
IR Spectrum U= . IR=? NAR Spectrum 6. a THS
What is the molar extinction coefficient at 625 nm for this copper (II) acetate solution? How was it determined? Standard Solution Concentration (M) Absorbance 1 0.025 0.049 2 0.050 0.153 3 0.100 0.242 4 0.200 0.499 5 0.250 0.694
See the attached photo
In general, we want to have absorptions less than or equal to 1. Given that an ethanol solution of compound Y (150.0 g/mol) in a 1.00 cm quartz cell has an extinction coefficient (E) of 23,150 at Amax=235 nm, what is the top concentration, in uM, we should consider for compound Y? Report your answer to the correct number of significant figures.
A 40-mL cigarette smoke sample was collected and made to react with 10 mL of the NOx indicator mixture solution. The color was allowed to develop and the absorbance reading a UV-Vis spectrophotometer at 550 nm. The absorbance reading of the sample was 0.570. Calculate: a. Concentration of NO₂ (in µg NO₂/mL) if the equation of the line from a standard calibration curve is: y = 1.259x + 0.0222 b. Concentration of NO₂ gas (in µg NO₂/L) in the gaseous sample
6. The UV-Vis absorption spectrum was measured for three different concentrations (10 mM, 20 mM, and 30 mM) of an analyte that we will call orangium as shown in the figure below. A 1.000 cm cuvette is used for all of the experiments. 1.00 0.90 0.80 0.70 0.60 a 0.50
UV: max 235 (ε 12,000) and max 314 (ε 120) EIMS: m/z 39 (31%), 41 (33%), 55 (37%), 69 (26%), 98 (100%), 99 (7%), 100 (0.2%) IR: Imm IR spectrum in CCl4 solvent 2950 cm-¹ 2000 4) RC=N 5) 0-H BAYEHUNIERI - R 1630 cm-¹ 1710 cm-¹ $10 4a) Which of the following heteroatoms that are definitely NOT present based on the EIMS data? (Circle all that apply). Br Cl FSI 0 4 continued) Please refer to data on preceding page. 4b) From the EIMS data what is the best estimate of the number of carbon atoms in this molecule? 4c) From the UV data, conjugated л-bonds are: definitely present definitely absent 4d) From the IR spectrum alone, which of the following functional groups can be definitely ruled OUT? Circle those that are ruled out and briefly explain why. 1) C=0 2) RC=CR 3) C=C cannot tell
*13-7_ A solution containing the complex formed between Bi(III) and thiourea has a molar absorptivity of 9.32 X 10³ L mol¹ cm¹ at 470 nm. 00.5 701 X 00.A 1910 919 juloa wot What is the absorbance of a 4.25 × 10-5 M : I solution of the complex at 470 nm in a 1.00-cm cell? (a) W (b) (alios mo-00.1) What is the percent transmittance of the solution described in (a)? (c) 200 What is the molar concentration of the complex in a solution that has the absorbance described in Torito or tovo (a) when measured at 470 nm in a 2.50-cm cell? (non?+ 1rd
Attempt to explain the main features of the H NMR spectrum of crotonic acid (4), Spec. 4. Deduce the stereochemistry of the carboxylic acid (CO₂H peak not shown). S ... 8 0 SPEC CHCHỊCH CÔ, H 4