Create 2 Programs, one in C++ and one in Python, to Solve two different Engineering Problems. Your two programs must include the following elements: 1. Welcome Message 2. Problem Description Message (background, required inputs & expected results) 3. Set/Capture Input Data 4. Perform the Main Process (corresponds to the Engineering Problem) 5. Display Results, feedback, and Comments (Based on results) 6. Goodbye Message

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Create 2 Programs, one in C++ and one in Python, to Solve two different Engineering Problems.
Your two programs must include the following elements:
1. Welcome Message
2. Problem Description Message
(background, required inputs & expected results)
3. Set/Capture Input Data
4. Perform the Main Process
(corresponds to the Engineering Problem)
5. Display Results, feedback, and Comments
(Based on results)
6. Goodbye Message
Transcribed Image Text:Create 2 Programs, one in C++ and one in Python, to Solve two different Engineering Problems. Your two programs must include the following elements: 1. Welcome Message 2. Problem Description Message (background, required inputs & expected results) 3. Set/Capture Input Data 4. Perform the Main Process (corresponds to the Engineering Problem) 5. Display Results, feedback, and Comments (Based on results) 6. Goodbye Message
Determine the force in each cable needed to
500-lb a.
support the 2.5-kN load.
Equations of Equilibrium :
4
F: 0; FCD-2.5 = 0
5
Fx = 0; FCA
Using the results FcD = 3.125 kN and then summing forces
along x and y axes we have
+
Fy= 0; 2F3
FCD=3.125 kN
-FCBO
3.125 3
FC FCB=F=0.988 KN
Ans
FCA FCB = F
= 0
Ans
1m
1m
FCB
FEA
3 m
9H
2.5 kN
C
8P
D
8H
y
Transcribed Image Text:Determine the force in each cable needed to 500-lb a. support the 2.5-kN load. Equations of Equilibrium : 4 F: 0; FCD-2.5 = 0 5 Fx = 0; FCA Using the results FcD = 3.125 kN and then summing forces along x and y axes we have + Fy= 0; 2F3 FCD=3.125 kN -FCBO 3.125 3 FC FCB=F=0.988 KN Ans FCA FCB = F = 0 Ans 1m 1m FCB FEA 3 m 9H 2.5 kN C 8P D 8H y
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