Course Code: BIO-121 Chapter 3: Molecules of Life (A) Complete the tables below: Polymer Polysaccharides Proteins Nucleic Acids What is the monomer subunit? Course Name: Principles Of Biology-1 Name the covalent bond which joins monomers Examples of molecules which belong to this class of macromolecules

Course Code: BIO-121 Chapter 3: Molecules of Life (A) Complete the tables below: Polymer Polysaccharides Proteins Nucleic Acids What is the monomer subunit? Course Name: Principles Of Biology-1 Name the covalent bond which joins monomers Examples of molecules which belong to this class of macromolecules

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter3: Biological Macromolecules

Section: Chapter Questions

Problem 14RQ: Cholesterol is an integral part of plasma membranes. Based on its structure, where is it found in...

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4. Course Code: BIO-121 Chapter 3: Molecules of Life Course Name: Principles Of Biology-1 Protein's function depends on its 3D shape. High temperature may result in protein denaturation. (i) Explain what is meant by "denatured". (ii) Explain why a protein may not be functional if it is denatured. (iii) Other than temperature, list the factors that can result in protein denaturation.
Essay question: Compare the 3-D structure of proteins with the 3-D structure of DNA
Chemistry PLEASE #6.
[Ten - Biomolecules] INSTRUCTIONS — Answer the following multiple-choice questions and EXPLAIN in 3-5 sentences why you chose that answer. — Answer properly Questions; Thomas was purifying an enzyme from a homogenate of muscle cells. He went through seven steps of purification and found that the enzyme activity was the same as the homogenate value. On the eighth step, when the protein washighly pure, the enzyme activity rose to five times that of the homogenate value. Can you suggest a possible reason? A. the homogenate assay was wrong B. step eight has co-purified an activator of the enzyme. C. the enzyme has an inhibitor present in the muscle cell homogenate D. the temperature at step eight was just right for the enzyme activity.
Exercise B: Peptide Bond Formation Figure 2 shows two individual amino acids, and then those same two amino acids after they have been linked together by a peptide bond to form a dipeptide. Addition of more amino acids linked by peptide bonds would form a polypeptide, the precursor to a functional protein. нн +| | || H-N-C-Ĉ-0 H. +! | || H-N-C-ċ –0 H. H H H +| | || H-N-C-C-N-C-C- + H CH2 CH2 H CH2 H. CH2 SH SH NH, NH, Figure 2. Formation of a peptide bond between two amino acids. Answer the below questions in your own document. 1. Which two amino acids are shown on the left side of Figure 2? Use the Figure 3.2 from your text to answer this. 2. To which chemical groups do these amino acids belong? 3. Were you able to identify their chemical characteristics based on your rules? If not, you should go back and revise your rules! On the dipeptide shown in Figure 2, label the peptide bond that was formed when the two individual amino acids were joined. Label the free amino and carboxyl…
Course Code: BIO-121 Chapter 3: Molecules of Life Course Name: Principles Of Biology-1 3. (i) Name the three components found in a nucleotide. (ii) State the differences between a DNA nucleotide and an RNA nucleotide.
Given: Cryo-EM structure of PCoV_GX spike glycoprotein 1. What can you tell me about the identity of the protein? 2. What is the importance of this protein?
Course Code: BIO-121 Chapter 3: Molecules of Life Course Name: Principles Of Biology-1 1. List the monomer(s) produced after hydrolysis of the following molecules: (i) (ii) cellulose lactose
Exercise B: Peptide Bond Formation Figure 3 shows two individual amino acids, and then those same two amino acids after they have been linked together by a peptide bond to form a dipeptide. Addition of more amino acids linked by peptide bonds would form a polypeptide, the precursor to a functional protein. нн H H O нно H O +| | || H-N-C-ċ-o + +| 1 || H-N-C-C +| | || Н-N—С- С—N—C—С H CH2 H CH2 H CH2 CH2 SH SH NH2 NH2 Figure 3. Formation of a peptide bond between two amino acids. Answer the below questions in your own document. • Which two amino acids are shown on the left side of Figure 3? Use Figure 2 to answer this. • To which chemical groups do these amino acids belong? Were you able to identify their chemical characteristics based on your rules? If not, you should go back and revise your rules! On the dipeptide shown in Figure 3, label the peptide bond that was formed when the two individual amino acids were joined. Label the free amino and carboxyl groups at the ends of this…
Exercise B: Peptide Bond Formation Figure 2 shows two individual amino acids, and then those same two amino acids after they have been linked together by a peptide bond to form a dipeptide. Addition of more amino acids linked by peptide bonds would form a polypeptide, the precursor to a functional protein. H H H. H H +| | H-N-Ċ- ċ-0 H-N-Ć- Ĉ-O H-N-Č -C. N-C-C- H CH2 H. CH2 H. CH2 H CH2 SH SH NH2 NH2 Figure 2. Formation of a peptide bond between two amino acids. Answer the below questions in your own document. F1. Which two amino acids are shown on the left side of Figure 2? Use the Figure They 3.2 from your text to answer this. 2. To which chemical groups do these amino acids belong? 3. Were you able to identify their chemical characteristics based on your rules? If not, you should go back and revise your rules! On the dipeptide shown in Figure 2, label the peptide bond that was formed when the two individual amino acids were joined. Label the free amino and carboxyl groups at the ends…
Course Code: BIO-121 Chapter 3: Molecules of Life Course Name: Principles Of Biology-1 2. State the difference between a saturated and unsaturated fatty acid.
Course Code: BIO121 Course Name: Principles of Biology I Read the question carefully first Answer the question-3(b) given chemical reaction according to the question (i) (ii) (iii) with step by step clear explanation. Enzyme X 3 (b) Given a chemical reaction: A + B- (i) (ii) (iii) Enzyme X can be used to catalyze the reaction above. Enzyme X binds to molecule A and B, and converts these molecules into product C. Using the lock and key model, explain how enzyme X is specific to its action. Predict what would happen to the rate of enzyme activity if the concentrations of molecule A and B are increased. Suggest ONE (1) way of how the activity of enzyme X can be controlled.