Coupling Endergonic & Exergonic Reactions in Metabolism (Hess's Law). Use the appropriate AG°' values below from the table. You have to pick the correct two equations in the table to obtain the desired equation (the hydrolysis of acetyl-CoA) below. Reaction AG° (kJ/mol) Oxaloacetate + acetyl-CoA + H20 → citrate + COASH + H* -32.2 Malate → fumarate + H20 3.8 Oxaloacetate + acetate → citrate -0.8 Malate + NAD* → oxaloacetate + NADH + H+ 29.7 Oxaloacetate + 2H* + 2e¯ → malate?- -32.04 Using the informațion in the table above, calculate AG" for the following reaction (the hydrolysis of acetyl-CoA): Acetyl-CoA + H2O → Acetate + COASH + H* AG" = ? 0.16 kJ/mol
Coupling Endergonic & Exergonic Reactions in Metabolism (Hess's Law). Use the appropriate AG°' values below from the table. You have to pick the correct two equations in the table to obtain the desired equation (the hydrolysis of acetyl-CoA) below. Reaction AG° (kJ/mol) Oxaloacetate + acetyl-CoA + H20 → citrate + COASH + H* -32.2 Malate → fumarate + H20 3.8 Oxaloacetate + acetate → citrate -0.8 Malate + NAD* → oxaloacetate + NADH + H+ 29.7 Oxaloacetate + 2H* + 2e¯ → malate?- -32.04 Using the informațion in the table above, calculate AG" for the following reaction (the hydrolysis of acetyl-CoA): Acetyl-CoA + H2O → Acetate + COASH + H* AG" = ? 0.16 kJ/mol
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Coupling Endergonic & Exergonic Reactions in Metabolism (Hess's Law). Use the appropriate AG°ʻ values below from the table. You have to pick the correct two equations
in the table to obtain the desired equation (the hydrolysis of acetyl-CoA) below.
Reaction
AG° (kJ/mol)
Oxaloacetate + acetyl-CoA + H20 → citrate + COASH + H*
Malate → fumarate + H20
-32.2
3.8
Oxaloacetate + acetate → citrate
-0.8
Malate + NAD* → oxaloacetate + NADH + H+
29.7
Oxaloacetate + 2H* + 2e¯ → malate?-
-32.04
Using the informațion in the table above, calculate AG" for the following reaction (the hydrolysis of acetyl-CoA):
Acetyl-CoA + H2O → Acetate + COASH + H*
AG" = ?
0.16 kJ/mol
-28.4 kJ/mol
-61.9 kJ/mol
31.4 kJ/mol
64.24 kJ/mol
-64.24 kJ/mol
-2.5 kJ/mol
28.4 kJ/mol
-31.4 kJ/mol
61.9 kJ/mol
-33.0 kJ/mol
2.5 kJ/mol
-31.54 kJ/mol
36.0 kJ/mol
33.0 kJ/mol
-0.16 kJ/mol
31.54 kJ/mol
-36.0 kJ/mol
OO O O O 000 0 00000 O000](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbd285f6f-67ec-4ffa-8e9b-700f12fa780d%2F6f70e74b-4792-486f-ac61-e78a12b524cd%2Fj0e8uwe_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Coupling Endergonic & Exergonic Reactions in Metabolism (Hess's Law). Use the appropriate AG°ʻ values below from the table. You have to pick the correct two equations
in the table to obtain the desired equation (the hydrolysis of acetyl-CoA) below.
Reaction
AG° (kJ/mol)
Oxaloacetate + acetyl-CoA + H20 → citrate + COASH + H*
Malate → fumarate + H20
-32.2
3.8
Oxaloacetate + acetate → citrate
-0.8
Malate + NAD* → oxaloacetate + NADH + H+
29.7
Oxaloacetate + 2H* + 2e¯ → malate?-
-32.04
Using the informațion in the table above, calculate AG" for the following reaction (the hydrolysis of acetyl-CoA):
Acetyl-CoA + H2O → Acetate + COASH + H*
AG" = ?
0.16 kJ/mol
-28.4 kJ/mol
-61.9 kJ/mol
31.4 kJ/mol
64.24 kJ/mol
-64.24 kJ/mol
-2.5 kJ/mol
28.4 kJ/mol
-31.4 kJ/mol
61.9 kJ/mol
-33.0 kJ/mol
2.5 kJ/mol
-31.54 kJ/mol
36.0 kJ/mol
33.0 kJ/mol
-0.16 kJ/mol
31.54 kJ/mol
-36.0 kJ/mol
OO O O O 000 0 00000 O000
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