A chemist fills a reaction vessel with 0.286 g calcium phosphate (Ca3(PO4)₂) solid, 0.954 M calcium (Ca²+) aqueous solution, and 0.992 M phosphate (PO³) aqueous solution at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy AG for the following chemical reaction: 2+ 3- Ca3(PO4),(s) ⇒ 3Ca²+ (aq) +2PO4³(aq) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule. KJ X

A chemist fills a reaction vessel with 0.286 g calcium phosphate (Ca3(PO4)₂) solid, 0.954 M calcium (Ca²+) aqueous solution, and 0.992 M phosphate (PO³) aqueous solution at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy AG for the following chemical reaction: 2+ 3- Ca3(PO4),(s) ⇒ 3Ca²+ (aq) +2PO4³(aq) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule. KJ X

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Use this information to complete the table below.
A student determines the value of the equilibrium constant to be 2.30 x 10¹6 for the following reaction. Ca(OH)2 (aq) + 2HCl(aq) → CaCl₂ (s) + 2H₂O(1) Based on this value of Keq AGO for this reaction is expected to be than zero. Calculate the free energy change for the reaction of 1.57 moles of Ca(OH)2 (aq) at standard conditions at 298 K. AGO rxn kJ
aqueous solution, and 0.545 g lead (II) bromide A chemist fills a reaction vessel with 0.390 M lead (II) (Pb2+) aqueous solution, 0.591 M bromide (Br) ad (PbBr2) solid at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy AG for the following chemical reaction: Pb2+(aq) + 2Br (aq) = PbBr₂ (s) Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule. pla 18 Ar
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A student determines the value of the equilibrium constant to be 1.98×107 for the following reaction. Fe(s) + 2HCI(aq)–FeCl(s) + H2(g) Based on this value of Keqi AG° for this reaction is expected to be (greater, less) than zero. Calculate the free energy change for the reaction of 1.54 moles of Fe(s) at standard conditions at 298K. AG°, kJ rxn
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A student determines the value of the equilibrium constant to be 4.09×10-18 for the following reaction. Fe;O4(s) + 4H2(g)→3FE(s) + 4H,O(g) Based on this value of Kegi AG° for this reaction is expected to be (greater, less) greater than zero. Calculate the free energy change for the reaction of 1.76 moles of Fe;0,(s) at standard conditions at 298K. AG°. rxn = 190.5 kJ
Ammonia can be produced by the reaction of hydrogen gas and nitrogen gas, as shown below: N2(g) + 3H2(g) → 2NH3(g) Given that the standard free energy of formation of NH3 (g) is -104 kJ/mol at 298 K, calculate the equilibrium constant, K, at this temperature. To express an answer in exponential notation, use E to indicate the exponent. For example, 3.0 x 103 would be written, 3.0E3.
The standard reaction free energy AG = -311. kJ for this reaction: P4(s) + 20 HF (g) 4 PF 5(g) + 10 H₂(g) → Use this information to complete the table below. Round each of your answers to the nearest kJ. reaction 2PF, (g) + 5H₂(g) → P₁ (s) + 10HF (g) 2 4 4PF, (g) + 10H₂(g) 3P (s) + 60HF (g) P(s) + 20HF (g) 4 12PF, (g) + 30H₂(g) 2 AGⓇ KJ kJ kJ x10 X 5
A chemist fills a reaction vessel with 0.137 g calcium phosphate (Ca, (PO,) solid, 0.349 M calcium (Ca ) aqueous solution, and 0.240 M phosphate (Po,") 3- POA aqueous solution at a temperature of 25.0°C. Under these conditions, calculate the reaction free energy AG for the following chemical reaction: Ca3 (PO4),(s) → 3Ca (aq) + 2PO, (aq) 4. Use the thermodynamic information in the ALEKS Data tab. Round your answer to the nearest kilojoule. kJ
In the Haber process, ammonia is synthesized from nitrogen and hydrogen: N2(8) + 3H2(g) → 2NH3(g) AG° at 298 K for this reaction is -33.3 kJ/mol. The value of AG at 298 K for a reaction mixture that consists of 1.9 atm N2, 1.6 atm H2, and 0.65 atm NH3 is O -1.8 O -104.5 O-3.86 x 103 O-7.25 x 10 -40.5
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