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ed under standard conditions, when the reaction is st ate the non-standard Free Energy change (AG) at 298 s of the three gases. Answer in kJ. 1) at 298 K partial pressure (atm) N2 1.0 H2 0.06 NH3 1.5

ed under standard conditions, when the reaction is st ate the non-standard Free Energy change (AG) at 298 s of the three gases. Answer in kJ. 1) at 298 K partial pressure (atm) N2 1.0 H2 0.06 NH3 1.5

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Calculating non-standard free energy (G)
In the previous question, you had to calculate the the standard Free Energy Change (AG°) in order to solve for the equilibrium constant, K, for the reaction: N2(g) + 3H2(g) 2NH3(g) This is the Free Energy measured under standard conditions, when the reaction is started with 1.0M of each of the three gases present. Calculate the non-standard Free Energy change (AG) at 298 K, given the following non- standard initial partial pressures of the three gases. Answer in kJ. AG° = -16.6 kJ/mol for NH3 (g) at 298 K partial pressure (atm) N2 1.0 H2 0.06 NH3 1.5 AG = Submit Answer Tries 0/99
Transcribed Image Text:In the previous question, you had to calculate the the standard Free Energy Change (AG°) in order to solve for the equilibrium constant, K, for the reaction: N2(g) + 3H2(g) 2NH3(g) This is the Free Energy measured under standard conditions, when the reaction is started with 1.0M of each of the three gases present. Calculate the non-standard Free Energy change (AG) at 298 K, given the following non- standard initial partial pressures of the three gases. Answer in kJ. AG° = -16.6 kJ/mol for NH3 (g) at 298 K partial pressure (atm) N2 1.0 H2 0.06 NH3 1.5 AG = Submit Answer Tries 0/99
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