import math number = int(input("Enter a number")) root = math.sqrt(number) if int(root+0.5)** 2 == number: print(number, "is a perfect square") else: print(number, "is not a perfect square") 'float' object is not callable can you help me fix the python code so I dont get this typeerror The original assignment was to create a perfect square python program and I have had so much trouble.
import math
number = int(input("Enter a number"))
root = math.sqrt(number)
if int(root+0.5)** 2 == number:
print(number, "is a perfect square")
else:
print(number, "is not a perfect square")
'float' object is not callable
can you help me fix the python code so I dont get this typeerror
The original assignment was to create a perfect square python program and I have had so much trouble.
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could you help me make it a loop. I understand you would use a statement like while or else to loop. Im trying to make it so if it is not a perfect square it will prompt the user to enter another number and try again?
by Bartleby ExpertI still get the TypeError 'float' object is not callable. Can you help me figure out why I keep getting this error. My program is also the same as the one that was corrected.
by Bartleby Expert
