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To demonstrate, let's apply the algorithm to n = 100 and see what happens. 1. 100 $ 3 is 1, so our partial answer is "1" 2. 100 / 3 is 33 3. 33 $ 3 is 0, so our partial answer is "01" 4. 33 / 3 is 11 5. 11 3 is 2, so our partial answer is "201" 6. 11 / 3 is 3 7. 3 3 is 0, so our partial answer is "0201" 8. 3 / 3 is 1 1 3 is 1, so our partial answer is "10201" 10. 1 / 3 is 0 9. 11. We reached 0. The final answer is "10201" We can verify tbat the final ans wer is correct because

To demonstrate, let's apply the algorithm to n = 100 and see what happens. 1. 100 $ 3 is 1, so our partial answer is "1" 2. 100 / 3 is 33 3. 33 $ 3 is 0, so our partial answer is "01" 4. 33 / 3 is 11 5. 11 3 is 2, so our partial answer is "201" 6. 11 / 3 is 3 7. 3 3 is 0, so our partial answer is "0201" 8. 3 / 3 is 1 1 3 is 1, so our partial answer is "10201" 10. 1 / 3 is 0 9. 11. We reached 0. The final answer is "10201" We can verify tbat the final ans wer is correct because

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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C. Create an int called zeroCount and assign it the value 0. This will count the number of zeroes in our answer string d. Create an int called oneCount and assign it the value 0. This will count the number of ones in our answer string Create an int called twoCount and assign it the value 0. This will count the number of twos in our answer string е. f. Create an int called currentNum and assign it the value initialNum 4. Print initialNum. 5. Create a while loop that terminates when currentNum is equal to 0 Within the while loop, create a local int variable called digit and assign to it currentNum 8 3 7. Use if-else if statements to do the following: 6. a. If digit is a 0, increment zeroCount If digit is a 1, increment oneCount c. If digit is a 2, increment twoCount Concatenate digit to the front of the string answer 9. Re-assign currentNum to currentNum / 3 b. 8. 10. After the while loop, use three print statements to output the following on separate lines: a. "Decimal representation: [initialNum]" b. "Ternary representation: [answer]" "[zeroCount] zeroes, [oneCount] ones, and [twoCount]twos" C. 11. Create an int variable digitSum and assign it to the sum of the digits in the ternary representation One way of evaluating this sum is 0* zeroCount +1• oneCount + 2 ° twoCount 12. Finally, use a switch statement to print one of the following statements according to the value of a. digitSum % 5: 0: "The ternary digits sum to a multiple of 5!" 1: "The ternary digits almost summed to a multiple 5!" 4: "So close!" a. b. C. d. Any other value: "Nope!" Example Outputs Please refer to the PE clarification thread on Ed for examples. HINT: To help debug your code, try inserting print statements in places where variables are changed. Feature Restrictions There are a few features and methods in Java that overly simplify the concepts we are trying to teach or break our auto grader. For that reason, do not use any of the following in your final submission: var (the reserved keyword) System.exit Import Restrictions You may not import anything for this homework assignment.
Transcribed Image Text:C. Create an int called zeroCount and assign it the value 0. This will count the number of zeroes in our answer string d. Create an int called oneCount and assign it the value 0. This will count the number of ones in our answer string Create an int called twoCount and assign it the value 0. This will count the number of twos in our answer string е. f. Create an int called currentNum and assign it the value initialNum 4. Print initialNum. 5. Create a while loop that terminates when currentNum is equal to 0 Within the while loop, create a local int variable called digit and assign to it currentNum 8 3 7. Use if-else if statements to do the following: 6. a. If digit is a 0, increment zeroCount If digit is a 1, increment oneCount c. If digit is a 2, increment twoCount Concatenate digit to the front of the string answer 9. Re-assign currentNum to currentNum / 3 b. 8. 10. After the while loop, use three print statements to output the following on separate lines: a. "Decimal representation: [initialNum]" b. "Ternary representation: [answer]" "[zeroCount] zeroes, [oneCount] ones, and [twoCount]twos" C. 11. Create an int variable digitSum and assign it to the sum of the digits in the ternary representation One way of evaluating this sum is 0* zeroCount +1• oneCount + 2 ° twoCount 12. Finally, use a switch statement to print one of the following statements according to the value of a. digitSum % 5: 0: "The ternary digits sum to a multiple of 5!" 1: "The ternary digits almost summed to a multiple 5!" 4: "So close!" a. b. C. d. Any other value: "Nope!" Example Outputs Please refer to the PE clarification thread on Ed for examples. HINT: To help debug your code, try inserting print statements in places where variables are changed. Feature Restrictions There are a few features and methods in Java that overly simplify the concepts we are trying to teach or break our auto grader. For that reason, do not use any of the following in your final submission: var (the reserved keyword) System.exit Import Restrictions You may not import anything for this homework assignment.
Problem Description Typically, we expect the numbers we use to be represented in the decimal numeral system, base-10. However, this is not the only way we can represent numbers. Computers will often store data in the binary numeral system, base-2. When tallying, people will often use the unary numeral system, base-1. For this assignment, we will be exploring the ternary numeral system, base-3. To represent a decimal number, which we will call n, in ternary, we can perform the following algorithm: Begin with an empty string to hold our answer Compute n modulo 3 and append it to the front of our answer Divide n by 3 (what kind of division should occur?) Repeat the above two steps until n is zero To demonstrate, let's apply the algorithm to n = 100 and see what happens. 1. 100 8 3 is 1, so our partial answer is "1" 2. 100 / 3 is 33 3. 33 $ 3 is 0, so our partial answer is "01" 4. 33 / 3 is 11 5. 11 % 3 is 2, so our partial answer is "201" 6. 11 / 3 is 3 3 8 3 is 0, so our partial answer is "0201" 8. 3 / 3 is 1 9. 1 3 is 1, so our partial answer is "10201" 10. 1 / 3 is 0 7. 11. We reached 0. The final answer is "10201" We can verify that the final answer is correct because 1.3 + 0• 3³ + 2•3² + 0 •3' +1·3° = 81 + 0 + 18 + 0 + 1 = 100 Notice how this conversion algorithm repeats the same two steps over and over (mod and division). This means we can implement it with iteration a.k.a. loopst Your assignment will consist of 2 main parts: Start with some arbitrary number in decimal and create the ternary string representation Print out information about the ternary representation Solution Description 1. Create a class called Ternary Create the main method 2. 3. Inside, create these variables: a. Create an int called initialNum and assign it any positive integer from 1-1000 (Please refer to the PE Clarification Thread on Ed for example output.) b. Create a String called answer and assign it to the empty string, "". This will hold our ternary representation as we build it
Transcribed Image Text:Problem Description Typically, we expect the numbers we use to be represented in the decimal numeral system, base-10. However, this is not the only way we can represent numbers. Computers will often store data in the binary numeral system, base-2. When tallying, people will often use the unary numeral system, base-1. For this assignment, we will be exploring the ternary numeral system, base-3. To represent a decimal number, which we will call n, in ternary, we can perform the following algorithm: Begin with an empty string to hold our answer Compute n modulo 3 and append it to the front of our answer Divide n by 3 (what kind of division should occur?) Repeat the above two steps until n is zero To demonstrate, let's apply the algorithm to n = 100 and see what happens. 1. 100 8 3 is 1, so our partial answer is "1" 2. 100 / 3 is 33 3. 33 $ 3 is 0, so our partial answer is "01" 4. 33 / 3 is 11 5. 11 % 3 is 2, so our partial answer is "201" 6. 11 / 3 is 3 3 8 3 is 0, so our partial answer is "0201" 8. 3 / 3 is 1 9. 1 3 is 1, so our partial answer is "10201" 10. 1 / 3 is 0 7. 11. We reached 0. The final answer is "10201" We can verify that the final answer is correct because 1.3 + 0• 3³ + 2•3² + 0 •3' +1·3° = 81 + 0 + 18 + 0 + 1 = 100 Notice how this conversion algorithm repeats the same two steps over and over (mod and division). This means we can implement it with iteration a.k.a. loopst Your assignment will consist of 2 main parts: Start with some arbitrary number in decimal and create the ternary string representation Print out information about the ternary representation Solution Description 1. Create a class called Ternary Create the main method 2. 3. Inside, create these variables: a. Create an int called initialNum and assign it any positive integer from 1-1000 (Please refer to the PE Clarification Thread on Ed for example output.) b. Create a String called answer and assign it to the empty string, "". This will hold our ternary representation as we build it
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