Copper(II) phthalocyanine (Cu(C32H16N8)) is treated with chlorine gas (Cl₂) according to the following reaction: Cu(C32H16N3) (S) + Cl₂(g) → Cu(C32 NgCl16) (S) + HCl(g) How many moles of hydrogen chloride would be produced by the complete chlorination of 4.38 grams of copper(II) phthalocyanine?

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Copper(II) phthalocyanine (Cu(C32H16N8)) is treated with chlorine gas
(Cl₂) according to the following reaction:
Cu(C32H16Ng) (S) + Cl₂(g) → Cu(C32 NgCl16) (S) + HCl(g)
How many moles of hydrogen chloride would be produced by the
complete chlorination of 4.38 grams of copper(II) phthalocyanine?
Transcribed Image Text:Copper(II) phthalocyanine (Cu(C32H16N8)) is treated with chlorine gas (Cl₂) according to the following reaction: Cu(C32H16Ng) (S) + Cl₂(g) → Cu(C32 NgCl16) (S) + HCl(g) How many moles of hydrogen chloride would be produced by the complete chlorination of 4.38 grams of copper(II) phthalocyanine?
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