connectMeModule 2 HW 15 (Section 7.3 Confidence Intervals for a|MATHHosted by ALEKS Corp.Population Proportion)Question 5 of 5Contaminated water: In a sample of 41 water specimens taken from a construction site, 26 containeddetectable levels of lead.(a) Construct a 98% confidence interval for the proportion of water specimens that contain detectablelevels of lead. Round the answer to at least three decimal places.(b) Construct a 90% confidence interval for the proportion of water specimens that contain detectablelevels of lead. Round the answer to at least three decimal places.(c) What is the effect of increasing the level of confidence on the width of the interval?Part 1 of 3(a) Construct a 98% confidence interval for the proportion of water specimens that containdetectable levels of lead. Round the answer to at least three decimal places.A 98% confidence interval for the proportion of water specimens that contain detectable levels oflead is

Given,n=41x=26p^=xnp^=2641=0.63411-p^=1-0.6341=0.3659α=1-0.98=0.02α2=0.01Z0.01=2.326 (from…

Answered: Contaminated water: In a sample of 41…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A computer store near campus is stocking its shelves and wants to know the relative proportions of students who use PCs vs Macs. A random sample of 60 students is surveyed, and each student is asked whether they use a PC or Mac more often. 55% select ”PC.” (a) What is the population and what is the sample in this study? (b) Calculate a 95% confidence interval for the proportion of UCI students that are PC users. (c) Provide an interpretation of this confidence interval in the context of this problem. (d) The confidence interval is pretty wide and leaves a lot of uncertainty over the proportion of UCIundergarduates who use PCs. With the goal to estimate a narrower 95% confidence interval, what is a simple change to this study that you could suggest for the next time that a similar survey is conducted?
2. You are going to construct a 90% confidence interval for the proportion ofadults that have a post-secondary education. You want the margin of errorto be .03. Your initial guess is that 35% of the population has a postsecondary education. What should the sample size be to achieve thismargin of error?
A study would like to investigate the risk of lung cancer in url. area and rural area. Assume the proportion of urban residents with lung cancer is p1, and the proportion of rural area residents with lung cancer is p2. If it is found that 20 of 200 adults in an urban community have lung cancer and 10 of 150 adults in the rural community have lung cancer. Find the 95% confidence interval for the difference in the proportions. Would you conclude that p1 is greater than p2? Select all correct answers. O "O" is not in the interval (C.I) O Yes, we can conclude p1 is greater than p2. O "0.1" is in the interval (C.I) O "O" is in the interval (C.I) Not enough information is given. O (-0.02431, 0.090972) O (21.48721, 22.90809) O No, we can't conclude p1 is greater than p2. O "0.1" is not in the interval (C.I) (-1.21908, 2.64790) O (-19.20998, -17.21458) Previous hp
Several years ago, 45% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,025 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,025 surveyed, 484 indicated that they were satisfied. Construct a 99% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed.
According to a poll, 79% of California adults (398 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the true proportion of California adults who feel that education is one of the top issues facing California. Find a 90% confidence interval for the population proportion. (Round your answers to three decimal places.) Additional Materials Reading
A. True or False? A researcher compares the BMI of two populations of individuals from different socioeconomic backgrounds and finds that the proportion of individuals considered obese and from a poor background is .37 (n = 112), and the proportion of individuals considered obese and from an affluent background is .27 (n = 87); a 95% confidence interval for the risk difference for obesity among members of the poor population compared to the affluent population is (-0.03, 0.23). B. Why is it true or false?
you conducted additional studies with these men and found the following: a. The RR for those who drank one drink per day was 1.50 (95% CI:1.32-1.67) in comparison to the abstainers. b. For those men who drank three or more drinks per day the RR compared to the abstainers was 4.20 (95% CI 2.68-5.85). Question: We can tell from the Confidence Intervals provided in #7 whether there are likely more people in the “one drink a day” group or the “3+ drinks per day” group. Which one likely has more people and how can we tell?
in a poll, 73% of California adults (367 out of 506 surveyed) believe that education is one of the main issues facing California. We want to construct a 90% confidence interval for the true proportion of California adults who believe that education is one of the main issues facing California.- I need help with finding a 90% confidence interval for the population proportion (I also have to round the answer to three decimal places)

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