According to a poll, 79% of California adults (398 out of 506 surveyed) feel that education is one of the top issues facing California. We wish to construct a 90% confidence interval for the trueproportion of California adults who feel that education is one of the top issues facing California.Find a 90% confidence interval for the population proportion. (Round your answers to three decimal places.)Additional MaterialsReading

Proportion of adult feel that education is one of the top issues facing California = 79%= 0.79Sample…

Answered: According to a poll, 79% of California…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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We wish to estimate what percent of adult residents in Ventura County like chocolate. Out of 300 adult residents sampled, 270 like chocolate. To construct a 90% confidence interval for the proportion (p) of adult residents who like chocolate in Ventura County, you need to use which one of the following calculator? Confidence Interval for a Population Proportion One-Way ANOVA Two Independent Proportions Comparison Two Independent Sample Means Comparison Given Statistics Two Dependent Sample Means Comparison Given Data Chi-Square Test for Independence Chi-Square Test for Goodness of Fit Two Independent Sample Means Comparison Given Data Confidence Interval for a Population Mean Given Statistics Hypothesis Test for a Population Mean Given Statistics Hypothesis Test for a Population Proportion Hypothesis Test for a Population Mean Given Data Confidence Interval for a Population Mean Given Data A. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents)…
Determine whether the statement below makes sense or does not make sense. Explain clearly. Based on our sample, the 95% confidence interval for the mean amount of television watched by adults in a nation is 3.5 to 4.1 hours per day. Therefore, there is 95% chance that the mean for all adults in the nation will fall somewhere in this range and a 5% chance that it will not. Choose the correct answer below. O A. The statement makes sense. There is 95% probability that the confidence interval limits actually contain the true value of the population mean, so the probability it does not fall in this range is 100% - 95% = 5%. O B. The statement does not make sense. The probability the population mean is greater than the upper limit is 5% and the probability it is less than the lower limit is 5%, so the probability it does not is 5% + 5% = 10%. O C. The statement makes sense. There is 5% probability that the confidence interval limits do not contain the true value of the sample mean, so the…
You create a 95% confidence interval for the proportion of a population. The confidence interval does not contain 0.10. This means that Group of answer choices a.You have evidence to conclude that the population proportion is equal to 0.10. b.You do not have evidence to conclude that the population proportion is equal to 0.10. c.You have evidence to conclude that the population proportion is not equal to 0.10. d.You do not have evidence to conclude that the population proportion is not equal to 0.10. e.The answer cannot be determined with the information given.
Statistics students surveyed 135 students at Tallahassee Community College. From their data we are 95% confident that between 44.7% and 61.9% of all TCC students are female. The students realize that this interval contains a large margin of error. What can they do to make a narrower interval? 1. Survey more students. 2. Use a 99% confidence level. 3. Survey more students and use a 99% confidence interval. 4. None of the other choices.
Defense Travel Syst... ▸ DBIDS | Web Portal -OR- Preservation Request TRICARE Online Topic 1: Results from surveys or opinion polls often report a range of values-the sample statistic plus or minus a margin of error (the resulting range is called a confidence interval). This tells us that the range is likely to contain the population parameter. How much wiggle room we provide is based on how much confidence we wish to have that the range contains the actual population mean. That confidence level is directly related to the middle "truth" area we will accept versus the dubious tail area we will reject-also known as alpha (x). The more confidence we wish to have -the more middle ground we will need to accept (more wiggle room)-thus a smaller tail area. If we insist on a larger alpha (more dubious tail area), we narrow the middle ground we will accept and thus provide less wiggle room-so the more likely it is that we will miss the true average (and, thus, we have a lower confidence level).…
We wish to estimate what percent of adult residents in Ventura County like chocolate. Out of 500 adult residents sampled, 429 like chocolate. To construct a 99% confidence interval for the proportion (p) of adult residents who like chocolate in Ventura County, you need to use which one of the following calculator? Hypothesis Test for a Population Proportion Confidence Interval for a Population Mean Given Data Confidence Interval for a Population Mean Given Statistics Chi-Square Test for Independence Hypothesis Test for a Population Mean Given Data Two Dependent Sample Means Comparison Given Data Confidence Interval for a Population Proportion Hypothesis Test for a Population Mean Given Statistics One-Way ANOVA Two Independent Sample Means Comparison Given Statistics Two Independent Sample Means Comparison Given Data Two Independent Proportions Comparison Chi-Square Test for Goodness of Fit Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents)…
Name: Statistics 1. An investigative reporter contacts a random sample of hotels, and finds a 95% confidence interval for the proportion of hotels in the United States that have reported having bedbugs is (0.04, 0.11). a. Interpret this confidence interval in context. F3 80 b. A national hospitality organization had reported that only 5% of hotels have experienced problems with bedbugs. Does this reporter have compelling evidence that the true proportion is really higher? Explain. c. How could the reporter estimate this proportion with a smaller margin of error? a. Identify the parameter, p, 2. To estimate how often someone runs a red light in Cyber City, a student watched traffic for a while at several randomly selected intersections. Drivers ran the red light during 43 of 240 light changes she observed. Q O Period: Quiz (ch 16+17) F4 9 F5 Page 1 / 2 c F6 8 + F7 Date: : DII F8 DD F9
A researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 480 college students showed that 23% of them had, or intended to, cheat on examinations. Find the 95% confidence interval for the population proportion. Round to four decimal places.
The figure to the right shows the results of a survey in which 2000 college graduates from the year 2016 were asked questions about employment. Construct 99% confidence intervals for the population proportion of college students who gave each response. Employment College students' responses to questions about employment Expect to stay at first employer for 3 or more years Completed an apprenticeship or intemship 70% 66% Employed in field of study 61% Feel underemployed 46% Prefer to work for a large company 15% The 99% confidence interval for the proportion of college students that expect to stay at their first employer for 3 or more years is (Round to three decimal places as needed.)
The figure to the right shows the results of a survey in which 2000 college graduates from the year 2016 were asked questions about employment. Construct 99% confidence intervals for the population proportion of college students who gave each response. Employment College students' responses to questions about employment Expect to stay at first employer for 3 or more years Completed an apprenticeship or internship 70% 66% Employed in field of study 61% Feel underemployed 46% Prefer to work for a large company 15% The 9970 Conuenit initivaliui int proportion un cuiityt diuutid inal txptul iu diay al ineli idi empivyti iui j'ui muit years is (0.01, 0.121). (Round to three decimal places as needed.) The 99% confidence interval for the proportion of college students that have completed an apprenticeship or internship is (J.). (Round to three decimal places as needed.)
Part 3: Putting the Pieces Together Some of the following questions might be more challenging, but we want you to wrestle through them and ask for clarification along the way. We hope that, ultimately, working through these problems will strengthen your understanding of the big ideas behind confidence intervals. 10. A researcher plans to survey a random sample of undergraduate students in order estimate the proportion of all undergraduate students who plan to apply to graduate school, and she will construct a confidence interval based on the data she gathers. Which one of the following combinations of sample size and confidence level will result in the most precise confidence interval? A.n= 500, confidence level = 95% B. n = 500, confidence level = 90% c.n= 1000, confidence level = 99% D. n 1000, confidence level = 90% E.n=200, confidence level = 99% 11. What proportion of adults are afraid of spiders? To estimate this unknown population proportion, a researcher gathers a random sample…

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