**Construct a Normal Probability Plot**For the following sample of observations on coating thickness for low-viscosity paint:- **Measurements:** 0.85, 0.86, 0.86, 1.02, 1.10, 1.11, 1.31, 1.31, 1.47, 1.48, 1.57, 1.63, 1.64, 1.73, 1.77, 1.84**Instructions:**1. **Use Statistical Software Tool (SALT):** - Click the "USE SALT" button to construct your normal probability plot using the given sample observations.2. **Determine the z Percentile:** - For each sample observation, calculate the z percentile. - Round your answers to two decimal places.**Sample Observations with Percentile Calculation:**- **Sample observation row 1:** - Observations: 0.85, 0.86, 0.86, 1.02, 1.10, 1.11, 1.31, 1.31- **Sample observation row 2:** - Observations: 1.47, 1.48, 1.57, 1.63, 1.64, 1.73, 1.77, 1.84**Empty Fields:**- Below each observation, there is space provided to write the calculated z percentile. You should fill these in after computation.

0.861.480.851.470.861.571.021.631.101.641.111.731.311.771.311.84

Answered: Construct a normal probability plot for…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Find the percent of the total area under the standard normal curve between the following z-scores. zequals=0.75 and zequals=1.2 The percent of the total area between zequals=0.75 and zequals=1.2 is enter your response here%. (Round to the nearest integer.)
Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity paint. 0.84 0.87 0.89 1.03 1.10 1.10 1.30 1.31 1.49 1.50 1.58 1.62 1.65 1.69 1.75 1.82 Determine the z percentile associated with each sample observation. (Round your answers to two decimal places.) Sample observation 0.84 0.87 0.89 1.03 1.10 1.10 1.30 1.31 z percentile Sample observation 1.49 1.50 1.58 1.62 1.65 1.69 1.75 1.82 z percentile
The accompanying data is on cube compressive strength (MPa) of concrete specimens. 112.4 97.0 92.7 86.0 102.0 99.3 95.8 103.5 89.0 86.7 A USE SALT (a) Is it plausible that the compressive strength for this type of concrete is normally distributed? O The normal probability plot is not acceptably linear, suggesting that a normal population distribution is not plausible. O The normal probability plot is not acceptably linear, suggesting that a normal population distribution is plausible. O The normal probability plot is acceptably linear, suggesting that a normal population distribution is not plausible. O The normal probability plot is acceptably linear, suggesting that a normal population distribution is plausible. (b) Suppose the concrete will be used for a particular application unless there is strong evidence that true average strength is less than 100 MPa. Should the concrete be used? Carry out a test of appropriate hypotheses. State the appropriate hypotheses. O Hoi u= 100 Hai u>…
b. Sketch a standard normal curve and shade the area under the curve that lies between - 3 and - 2.1. Choose the correct graph below. А. В. С. OD. - 2.1 2.1 O 2.1 3 O 2.1 3 The area that lies between - 3 and - 2.1 is 0.98 (Round to four decimal places as needed.) N
Which way of dispensing champagne, the traditional vertical method or a tilted beer-like pour, preserves more of the tiny gas bubbles that improve flavor and aroma? The following data was reported in an article. Type of Pour n Mean (g/L) SD 0.6 Traditional 4 Slanted Traditional 4 0.4 0.2 Slanted 4 0.1 Assume that the sampled distributions are normal. Temp (°C) 18 18 12 12 LUSE SALT (a) Carry out a test at significance level 0.01 to decide whether true average CO₂, loss at 18°C for the traditional pour differs from that for the slanted pour. (Use μ, for the traditional pour and State the relevant hypotheses. OH₂H₂H₂ 0 OHH₁-H₂0 H₂H₁-H₂=0 OH₂H₁ H₂=0 H₂H₁ H₂ <0 (b) Repeat the test of hypotheses suggested in (a) for the 12° temperature. Is the conclusion different from that for the 18° temperature? Note: The 12° result was reported in the popular media. (Use u, for the traditional pour and for the slanted pour.) State the relevant hypotheses. OHH, H₂ <0 H₂₁₂4₁₂4₂₁₂=0 - OH₂H₁-H₂=0 H₂H₂H₂ #0…
Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity paint. 0.82 0.87 0.90 1.02 1.11 1.14 1.31 1.33 1.47 1.48 1.61 1.63 1.64 1.72 1.74 1.84 Determine the z percentile associated with each sample observation. (Round your answers to two decimal places.) Sample observation 0.82 0.87 0.90 1.02 1.11 1.14 1.31 1.33 z percentile Sample observation 1.47 1.48 1.61 1.63 1.64 1.72 1.74 1.84 z percentile
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Consider the following sample of observations on coating thickness for low-viscosity paint. 0.83 0.88 0.88 1.03 1.09 1.21 1.29 1.31 1.42 1.49 1.59 1.62 1.65 1.71 1.76 1.83 Assume that the distribution of coating thickness is normal (a normal probability plot strongly supports this assumption). (c) Calculate a point estimate of the value that separates the largest 10% of all values in the thickness distribution from the remaining 90%. [Hint: Express what you are trying to estimate in terms of μ and σ.] (Round your answer to four decimal places.) (d) Estimate P(X < 1.2), i.e., the proportion of all thickness values less than 1.2. [Hint: If you knew the values of μ and σ, you could calculate this probability. These values are not available, but they can be estimated.] (Round your answer to four decimal places.) (e) What is the estimated standard error of the estimator that you used in part (b)? (Round your answer to four decimal places.)
Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity paint. 0.84 0.89 0.90 1.02 1.08 1.14 1.28 1.31 1.47 1.47 1.60 1.62 1.66 1.73 1.75 1.81 Determine the z percentile associated with each sample observation. (Round your answers to two decimal places.) Sample observation 0.84 0.89 0.90 1.02 1.08 1.14 1.28 1.31 z percentile Sample observation 1.47 1.47 1.60 1.62 1.66 1.73 1.75 1.81 z percentile

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