A pharmaceutical company makes tranquilizers. It is assumed that the distribution for the length of time they last is approximately normal. Researchers in a hospital used the drug on a random sample o9 patients. The effective period of the tranquilizer for each patient (in hours) was as follows: 2.7; 2.9; 3.1; 2.3; 2.3; 2.2; 2.8; 2.1; and 2.4.NOTE: If you are using a Student's t-distribution, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.)O Part (a)(i) Round your answer to two decimal places.X =(rounded to two decimal places)(ii) Round your answer to two decimal places.Sy =(roded to two decimal places)(iii) Enter an exact number as an integer, fraction, or decimal.n =(iv) Enter an exact number as an integer, fraction, or decimal.n - 1 = Construct a 95% confidence interval for the population mean length of time.(i) State the confidence interval. (Round your answers to two decimal places.)(ii) Sketch the graph.aC.L. =(iii) Calculate the error bound. (Round your answer to two decimal places.)+ Part (f)||

Name: A pharmaceutical company makes tranquilizers. It is assumed that the
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: A pharmaceutical company makes tranquilizers. It is assumed that the distribution for the length of time they last is approximately normal. Researchers in a hospital used the drug on a random sample o9 patients. The effective period of the tranquili

Answered: Image /qna-images/answer/1c2f594e-1727-4317-9abb-4cff75561a71.jpg

Math

Statistics

Construct a 95% confidence interval for the population mean length of time. (i) State the confidence interval. (Round your answers to two decimal places.) (ii) Sketch the graph. a C.L. 2 (iii) Calculate the error bound. (Round your answer to two decimal places.) + Part (f)

Construct a 95% confidence interval for the population mean length of time. (i) State the confidence interval. (Round your answers to two decimal places.) (ii) Sketch the graph. a C.L. 2 (iii) Calculate the error bound. (Round your answer to two decimal places.) + Part (f)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

How often do we trust a brand recommended online? Let p represent the proportion of the time a consumer trusts a brand that showed up on their social media feed. USE SALT (a) If you have no preliminary estimate for p, how many participants should you include in a random sample to be 80% sure that the point estimate will be within a distance of 0.09 from p? (Round your answer up to the nearest whole number.) X participants (b) Suppose that a report stated that 73% of consumers trust a brand recommended on their social media feed. Using this estimate for p, how many participants should you include in a random sample to be 80% sure that the point estimate will be within a distance of 0.09 from p? (Round your answer up to the nearest whole number.) Xparticipants Need Help? Read It Submit Answer
The accompanying data represent the total compensation for 12 randomly selected chief executive officers (CEOS) and the company's stock performance. Use the data to complete parts (a) through (d). E Click the icon to view the data table. (a) Treating compensation as the explanatory variable, x, use technology to determine the estimates of Bo and B,- The estimate of B, is (Round to three decimal places as needed.) Data Table of Compensation and Stock Performante Compensation Company (millions of dollars) Return (%) O Stock A 14.71 75.73 В 4.02 64.29 C 6.55 141.81 D 1.32 30.73 1.73 10.75 2.43 29.05 12.26 0.56 7.07 66.32 9.51 56.31 J 3.83 58.48 K 21.29 21.52 6.63 31.85 Print Done
6:56 (a) Which variable is the explanatory variable? One of the biggest factors in determining the value of a home is the square footage. The accompanying data represent the square footage and selling price (in thousands of dollars) for a random sample of homes for sale in a certain region. Complete parts (a) through (h) below. Click the icon to view the housing data. Square Footage Selling Price (b) Draw a scatter diagram of the data. Choose the correct scatter diagram below. O A. АУ 4500- 1000- ...m 1000 4500 Data Table Square Footage, x 2148 3231 1177 1988 3064 2735 4146 2215 2625 1629 1773 3887 Print B. AX 4500+ 1000+ 150 ● ↓ ||| = 750 Done (c) Determine the linear correlation coefficient between square footage and asking price. r = 0.905 B. No a house of square feet is not possible. (Type an integer or a simplified fraction.) Ау 750- Selling Price ($000s), y D 371.1 382.2 197.6 339.9 614.9 364.7 632.7 377.7 427.5 285.9 268.9 701.4 150+ 1000 A. No-a house of square feet is outside…
Lecture(12.8A) A researcher thinks that people have become more anxious when they hear about violent crime in the news. He asked a group of random participants to fill out two questioners. One questionere measured anxiety on a point scale from 1 to 10 with high anxiety resuting in higher scores. The other questionare asked participants to report the incidents of violent crime they had heard about (throuh media or face- to-face cummincation) in the last two weeks. The researcher gave the participants a score based on the total number of incidents reported. (1) What type of test should the researcher use to test this hypothesis.? (2) What would be the null and alternative hypotheses for this study? (Select two answers for each) (a) Z test (b)single sample t test (c)dependent sample t-test (d) independent sample t -test (e) ANOVA (f) Pearson correlation t-test (roe) (g) Chi Square goodness of fit test. (h)Chi Square test for independece (i)Ho: roe<=0…
asap please
Help for part B
Statistics in Science
Q-4)Show all the steps for the problem.
Show complete solution
solve for p-value please i need it asap
State whether the standardized test statistic t indicates that you should reject the null hypothesis. Explain. (a) t =1.667 (b) t =0 (c) t= -1.552 (d) t= -1.705 (look at image below)
In regression, the difference between the confidence interval and prediction interval formulas is Multiple Choice the prediction interval is the square root of the confidence interval the addition of 1 to the quantity under the radical sign no difference the prediction interval uses and the confidence interval uses r