Consider these reactions, where M represents a generic metal. 2 M(s) + 6HCl(aq) → 2 MC1₂ (aq) + 3 H₂(g) HCl(g) HCl(aq) H₂(g) + Cl₂(g) →→→ 2 HCI(g) MCI, (s) → MC1₂ (aq) Use the given information to determine the enthalpy of the reaction 2 M(s) + 3 Cl₂(g) →→→ 2 MC13 (s) 1. 2. 3. 4. - = -896.0 kJ ΔΗ, AH₂ = -74.8 kJ AH3 = -1845.0 kJ AH4 = -283.0 kJ
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![Here are the provided chemical reactions, where M represents a generic metal:
1. \( 2M(s) + 6HCl(aq) \rightarrow 2MCl_3(aq) + 3H_2(g) \)
\( \Delta H_1 = -896.0 \, \text{kJ} \)
2. \( HCl(g) \rightarrow HCl(aq) \)
\( \Delta H_2 = -74.8 \, \text{kJ} \)
3. \( H_2(g) + Cl_2(g) \rightarrow 2HCl(g) \)
\( \Delta H_3 = -1845.0 \, \text{kJ} \)
4. \( MCl_3(s) \rightarrow MCl_3(aq) \)
\( \Delta H_4 = -283.0 \, \text{kJ} \)
Use the given information to determine the enthalpy of the reaction:
\[ 2M(s) + 3Cl_2(g) \rightarrow 2MCl_3(s) \]
To solve for the enthalpy of the desired reaction \((2M(s) + 3Cl_2(g) \rightarrow 2MCl_3(s))\), we'll need to apply Hess's Law. Carefully combining the given reactions, we will eliminate intermediates and achieve the target reaction while summing the enthalpy changes appropriately. Hess's Law allows us to add or subtract the provided reactions such that they sum to the product reaction while also combining the associated enthalpy changes to find the overall enthalpy change for the target reaction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbbccee3c-a9d1-4424-96e1-9881a48faaa2%2F46c2e542-0954-4071-be12-f32b040a691d%2F0o6c9yf_processed.png&w=3840&q=75)
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