A 0.810-g piece of lithium metal is dropped into a mixture of 50.0 gwater and 50.0 g ice, both at 0°C. The reaction is2 Li(s) + 2 H₂O(1) → 2 LiOH(aq) + H₂(g) AH = 446 kJ/molAssuming no heat is lost to the surroundings, and that the final mixturehas a specific heat capacity of 4.18 J/g °C, calculate the finaltemperature in °C. The enthalpy of fusion for ice is 6.02 kJ/mol.

The moles of Li can be calculated as,mass of lithium, Li = 0.870 gMolar mass of Li= 6.941 g/molMoles…

0.810-g piece of lithium metal is dropped into a mixture of 50.0 g ater and 50.0 g ice, both at 0°C. The reaction is Li(s) + 2 H₂O(1)→→ 2 LiOH(aq) + H₂(g) AH =446 kJ/mol ssuming no heat is lost to the surroundings, and that the final mixture as a specific heat capacity of 4.18 J/g.°C, calculate the final emperature in °C. The enthalpy of fusion for ice is 6.02 kJ/mol.

0.810-g piece of lithium metal is dropped into a mixture of 50.0 g ater and 50.0 g ice, both at 0°C. The reaction is Li(s) + 2 H₂O(1)→→ 2 LiOH(aq) + H₂(g) AH =446 kJ/mol ssuming no heat is lost to the surroundings, and that the final mixture as a specific heat capacity of 4.18 J/g.°C, calculate the final emperature in °C. The enthalpy of fusion for ice is 6.02 kJ/mol.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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