Consider the two lenses shown in Figure 2. An object is placed on the left at coordinate x = 0. A converging lens with focal length f = 8 cm is placed at coordinate x = 10 cm. A diverging lens with focal length f2 = -8 cm is placed at coordinate x = 30 cm. fi = 8 f2 = -8 x = 0 10 30 Figure 2 (Not to Scale) a) Calculate the x coordinate of the final image for the two-lens system. Note that the figure is not to scale. Therefore, ray tracing on the figure will not be accurate. b) If the height of the object is 2 cm, what is the height of the final image? Is the final image inverted or upright?
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- An object 1.40 cm high is held 3.00 cm from a person's cornea, and its reflected image is measured to be 0.167 cm high. What is the magnification? magnification: Where is the image? image distance: cm Find the magnitude of the radius of curvature of the convex mirror formed by the cornea. magnitude of radius of curvature: cm Note: This technique is used by optometrists to measure the curvature of the cornea for contact lens fitting. The instrument used is called a keratometer, or curve measurer.Shown in the figure below is a system containing two lenses and an object. The focal lengths of the two lenses are f1 = -19 cm and f2 = 9.5 cm. The two lengths indicated in the figure are L1 = 28.5 cm and L2 = 15.2 cm. Determine all the following about the image from the first lens only:Object distance for the first lens, d01. cmImage distance for the first lens, di1. cmMagnification of the first lens, m1. The second lens uses the image from the first lens as its object. Determine all the following about the image from the second lens:Object distance for the second lens, d01. cmImage distance for the second lens, di1. cmMagnification of the second lens, m1. Determine the magnification of the whole system, mtot. Select the correct attributes of the final image of the system: virtual real enlarged shrunk upside down right side upShown in the figure below is a system containing two lenses and an object. The focal lengths of the two lenses are f₁ = 17 cm and f₂ = -8.5 cm. The two lengths indicated in the figure are L₁ = 25.5 cm and L2 = 13.6 cm. 41 f1 L₂ f2 Determine all the following about the image from the first lens only: Object distance for the first lens, do1. Image distance for the first lens, di1. cm cm Magnification of the first lens, m1. The second lens uses the image from the first lens as its object. Determine all the following about the image from the second lens: Object distance for the second lens, do1. Image distance for the second lens, di1. cm cm Magnification of the second lens, m₁. Determine the magnification of the whole system, mtot Select the correct attributes of the final image of the system: O real ○ virtual enlarged O shrunk O right side up O upside down NOTE: Throughout the problem be careful with the sign of every quantity.
- A converging lens has a focal length of 4.0 cm A 1.5 cm object is placed 6.0 cm to the left of the lens (as shown in the diagram below) Part A The distance of the image will be ανα ΑΣφ d; = cm Submit Request Answer Part B The height of the image will be Πνη ΑΣφ ? h4 = cm Submit Request Answer Part C The image is and O real, upright O real, inverted O virtual, inverted O virtual, uprightAssessment: Solve the following problems in a sheet of paper. 1. Determine the image distance and image height for a 5.5-cm tall object placed 54.0-cm from a converging lens having a focal length of 20.0 cm. 2. Determine the image distance and image height for a 5.0-cm tall object placed 48.0-cm from a converging lens having a focal length of 24.0 cm. 3. Determine the image distance and image height for a 4.8-cm tall object placed 26.0-cm from a converging lens having a focal length of 16.0 cmTwo lenses are separated by 50 cm. Lens 1 is convex and has a radius of curvature of magnitude 30 cm. Lens 2 is concave and has a radius of curvature of magnitude 40 cm and is located to the right of Lens 1. An object is located 20 cm to left of lens 1. Find the location of the final image of the object. What is the magnification of the final image?
- An object (height = 5.0 cm) and its image are on opposite sides of a converging lens. The object is located 11.0 cm from the lens. The image is located 5.3 cm from the lens. Determine the image height (in cm). Enter the numerical part of your answer to two significant figures. Hint: Remember that the sign of the image height is significant.2. 11.3 cm,-0.4 cm 2. A concave mirror has f = 10.5 cm. An object that is 5.2 cm tall is placed 1.5 m away from the mirror. Sketch the ray diagram. Find image height and distance. Describe image.A fortuneteller looks through her crystal (n = 1.50) ball with a 4 cm radius centered at x = 0. An object at x = -16 cm is viewed from some positiondown the positive x-axis. Where does she see the image? Give the x-coordinate of the image position. The answer is 9.6 cm, but I can't seem to get the right answer.
- cem 1 1 of 1 Use this information for parts G, H and I. The sideview mirror on your car is convex. When looking in this mirror, you see a car that has an actual distance of 100 m behind you (the distance from the car to the mirror) and the image appears to be only -1.961 m from the mirror. Part G What is the focal length of this mirror? Answer in units of m to four significant figures. Do not Include the units symbol. Submit Request Answer Part H If the image of the car appears to be 2.941×10¬2 m tall, what is the height of the actual car? Answer in units of m to four significant figures. Do not include the units symbol. ? Submit Request Answer Part IAn object is 8 cm in front of a diverging lens with a focal length of -7 cm. You may want to review (Pages 973-978). Constants Part A Determine the location of the image. Express your answer to two significant figures and include the appropriate units. Ti μA Units s' = Value Submit Request AnswerI2