Consider the reaction below to answer the following questions. When dichlorocarbene is generated in the presence of an alkene, a dichlorocyclopropane is formed. Cl Ã. H H of dichlorocarbene, :CCl₂. Show all H₂C 1 H CH3 1 + CHCl3 C=C H КОН. H₂C-- Write the complete stepwise mechanism for the formation intermediate structures and show all electron flow with arrows. CH3

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**Reaction Mechanism for Formation of Dichlorocarbene**

**Reaction Overview:**

The reaction involves the generation of dichlorocarbene in the presence of an alkene. The reaction leads to the formation of a dichlorocyclopropane compound.

**Chemical Reaction:**

\[ \text{H}_3\text{C} - \text{CH} = \text{CH} - \text{CH}_3 + \text{CHCl}_3 \xrightarrow{\text{KOH}} \]

This transforms into a dichlorocyclopropane structure with the incorporation of a dichlorocarbene (:CCl₂).

**Detailed Explanation:**

1. **Starting Materials:**
   - An alkene (2-butene): \(\text{H}_3\text{C}-\text{CH}=\text{CH}-\text{CH}_3\).
   - Chloroform (\(\text{CHCl}_3\)) in the presence of potassium hydroxide (\(\text{KOH}\)).

2. **Formation of Dichlorocarbene:**
   - \(\text{KOH}\) deprotonates chloroform, forming a carbanion intermediate.
   - Loss of a chloride ion produces the active dichlorocarbene species, :CCl₂.
   
3. **Reaction with Alkene:**
   - The dichlorocarbene (:CCl₂) inserts into the double bond of the alkene.
   - This results in the formation of a cyclopropane ring with two chlorine atoms attached.

4. **Final Product:**
   - A dichlorocyclopropane structure, where the previously double-bonded carbons are now part of a three-membered ring.

**Visualization of Mechanism:**

In the diagram:
- The alkene, \(\text{H}_3\text{C} - \text{CH} = \text{CH} - \text{CH}_3\), reacts with \(\text{CHCl}_3\) under basic conditions.
- The resulting product is a cyclopropane ring with two chlorine atoms situated on one of the carbons in the three-membered ring.

The diagram indicates the conversion of the alkene to the cyclopropane with arrows showing electron flow during the formation of the dichlorocyclopropane. Each step in
Transcribed Image Text:**Reaction Mechanism for Formation of Dichlorocarbene** **Reaction Overview:** The reaction involves the generation of dichlorocarbene in the presence of an alkene. The reaction leads to the formation of a dichlorocyclopropane compound. **Chemical Reaction:** \[ \text{H}_3\text{C} - \text{CH} = \text{CH} - \text{CH}_3 + \text{CHCl}_3 \xrightarrow{\text{KOH}} \] This transforms into a dichlorocyclopropane structure with the incorporation of a dichlorocarbene (:CCl₂). **Detailed Explanation:** 1. **Starting Materials:** - An alkene (2-butene): \(\text{H}_3\text{C}-\text{CH}=\text{CH}-\text{CH}_3\). - Chloroform (\(\text{CHCl}_3\)) in the presence of potassium hydroxide (\(\text{KOH}\)). 2. **Formation of Dichlorocarbene:** - \(\text{KOH}\) deprotonates chloroform, forming a carbanion intermediate. - Loss of a chloride ion produces the active dichlorocarbene species, :CCl₂. 3. **Reaction with Alkene:** - The dichlorocarbene (:CCl₂) inserts into the double bond of the alkene. - This results in the formation of a cyclopropane ring with two chlorine atoms attached. 4. **Final Product:** - A dichlorocyclopropane structure, where the previously double-bonded carbons are now part of a three-membered ring. **Visualization of Mechanism:** In the diagram: - The alkene, \(\text{H}_3\text{C} - \text{CH} = \text{CH} - \text{CH}_3\), reacts with \(\text{CHCl}_3\) under basic conditions. - The resulting product is a cyclopropane ring with two chlorine atoms situated on one of the carbons in the three-membered ring. The diagram indicates the conversion of the alkene to the cyclopropane with arrows showing electron flow during the formation of the dichlorocyclopropane. Each step in
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