Consider the proposed mechanism for the decomposition reaction 2 H2O2(aq)→ 2 H2O(1) + O2(g) in the presence of I-(aq). What is the rate law for this reaction? A) rate = k[H2O:] Step 1 (slow) B) rate = k[H2O:]? H2O2(aq) + l-(aq) H2O(1) + IO-(aq) C) rate = k[H2O:][] Step 2 (fast) D) rate = k[H2O:][IO] H2O2(aq) + 10-(aq) → H2O(1) + O2(g) + I-(aq) E) rate = K[H:O:]°[I¬/[H±O]
Consider the proposed mechanism for the decomposition reaction 2 H2O2(aq)→ 2 H2O(1) + O2(g) in the presence of I-(aq). What is the rate law for this reaction? A) rate = k[H2O:] Step 1 (slow) B) rate = k[H2O:]? H2O2(aq) + l-(aq) H2O(1) + IO-(aq) C) rate = k[H2O:][] Step 2 (fast) D) rate = k[H2O:][IO] H2O2(aq) + 10-(aq) → H2O(1) + O2(g) + I-(aq) E) rate = K[H:O:]°[I¬/[H±O]
Chemistry
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Consider the proposed mechanism for the decomposition reaction 2 H2O2(aq) → 2
H2O(I) + O2(g) in the presence of l-(aq). What is the rate law for this reaction?
A) rate =
K[H±O2]
Step 1 (slow)
B) rate =
K[H±O2]²
H2O2(aq) + 1-(aq)
H20(1) + 10-(aq)
C) rate
= k[H±O:][I]
Step 2 (fast)
D) rate = k[H2O2][IO]
H2O2(aq) + 10-(aq) ·
- H20(1) + O2(g) + I-(aq)
E) rate =
k[H±O•]°[I¬/[H±O]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F85f382e3-405b-4399-98e8-b7975548af1a%2F46823418-3083-4cb6-a245-edf72dc3290f%2Fsw8kpdo_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the proposed mechanism for the decomposition reaction 2 H2O2(aq) → 2
H2O(I) + O2(g) in the presence of l-(aq). What is the rate law for this reaction?
A) rate =
K[H±O2]
Step 1 (slow)
B) rate =
K[H±O2]²
H2O2(aq) + 1-(aq)
H20(1) + 10-(aq)
C) rate
= k[H±O:][I]
Step 2 (fast)
D) rate = k[H2O2][IO]
H2O2(aq) + 10-(aq) ·
- H20(1) + O2(g) + I-(aq)
E) rate =
k[H±O•]°[I¬/[H±O]
Expert Solution
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Step 1
In this reaction, we will consider step 1 for writing our rate law equation. Step 1 is a slow process which is also our rate-determining step.
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