Consider the proposed mechanism for the decomposition reaction 2 H2O2(aq)→ 2 H2O(1) + O2(g) in the presence of I-(aq). What is the rate law for this reaction? A) rate = k[H2O:] Step 1 (slow) B) rate = k[H2O:]? H2O2(aq) + l-(aq) H2O(1) + IO-(aq) C) rate = k[H2O:][] Step 2 (fast) D) rate = k[H2O:][IO] H2O2(aq) + 10-(aq) → H2O(1) + O2(g) + I-(aq) E) rate = K[H:O:]°[I¬/[H±O]

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Consider the proposed mechanism for the decomposition reaction 2 H2O2(aq) → 2
H2O(I) + O2(g) in the presence of l-(aq). What is the rate law for this reaction?
A) rate =
K[H±O2]
Step 1 (slow)
B) rate =
K[H±O2]²
H2O2(aq) + 1-(aq)
H20(1) + 10-(aq)
C) rate
= k[H±O:][I]
Step 2 (fast)
D) rate = k[H2O2][IO]
H2O2(aq) + 10-(aq) ·
- H20(1) + O2(g) + I-(aq)
E) rate =
k[H±O•]°[I¬/[H±O]
Transcribed Image Text:Consider the proposed mechanism for the decomposition reaction 2 H2O2(aq) → 2 H2O(I) + O2(g) in the presence of l-(aq). What is the rate law for this reaction? A) rate = K[H±O2] Step 1 (slow) B) rate = K[H±O2]² H2O2(aq) + 1-(aq) H20(1) + 10-(aq) C) rate = k[H±O:][I] Step 2 (fast) D) rate = k[H2O2][IO] H2O2(aq) + 10-(aq) · - H20(1) + O2(g) + I-(aq) E) rate = k[H±O•]°[I¬/[H±O]
Expert Solution
Step 1

 

In this reaction, we will consider step 1 for writing our rate law equation. Step 1 is a slow process which is also our rate-determining step.

 

Chemistry homework question answer, step 1, image 1

 

 

 

 

  

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