3. An experiment was carried out to determine the rate law for the following reaction: 2NO( )+0( ) → 2NO() Where the rate law is: Rate = k[NO] [0] The experiment was repeated three times and the following data recorded: Experiment # Initial [NO] (M) Initial [0] (M) Rate (M/s) 1 0.015 936 0.015 2 0.030 0.015 3 0.015 0.030 Determine the value of x in the rate law (order of reaction with respect to NO) by comparing experiments 1 and 2 in Equation 13 reaction with respect to O2) by comparing experiments 1 and 3 in equation 13. 0.048 0.192 0.096
3. An experiment was carried out to determine the rate law for the following reaction: 2NO( )+0( ) → 2NO() Where the rate law is: Rate = k[NO] [0] The experiment was repeated three times and the following data recorded: Experiment # Initial [NO] (M) Initial [0] (M) Rate (M/s) 1 0.015 936 0.015 2 0.030 0.015 3 0.015 0.030 Determine the value of x in the rate law (order of reaction with respect to NO) by comparing experiments 1 and 2 in Equation 13 reaction with respect to O2) by comparing experiments 1 and 3 in equation 13. 0.048 0.192 0.096
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![3. An experiment was carried out to determine the rate law for the following reaction:
19152
2NO( )+0( ) → 2NO( )
Where the rate law is:
par
Rate = k[NO] [0]
The experiment was repeated three times and the following data recorded:
Experiment #
Initial [NO] (M)
Initial [0] (M)
Rate (M/s)
1
ullo2 M0.015
0.015
2
0.030
0.015
3
0.015
0.030
of in
Determine the value of x in the rate law (order of reaction with respect to NO) by
comparing experiments 1 and 2 in Equation 13 reaction with respect to O₂) by
comparing experiments 1 and 3 in equation 13.
0.048
0.192
0.096](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fded65200-a4a0-48cc-8483-b7d6b114e86a%2Fc9b12750-da9e-43e7-ae4c-06ca05fb3750%2Fa2zcakc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. An experiment was carried out to determine the rate law for the following reaction:
19152
2NO( )+0( ) → 2NO( )
Where the rate law is:
par
Rate = k[NO] [0]
The experiment was repeated three times and the following data recorded:
Experiment #
Initial [NO] (M)
Initial [0] (M)
Rate (M/s)
1
ullo2 M0.015
0.015
2
0.030
0.015
3
0.015
0.030
of in
Determine the value of x in the rate law (order of reaction with respect to NO) by
comparing experiments 1 and 2 in Equation 13 reaction with respect to O₂) by
comparing experiments 1 and 3 in equation 13.
0.048
0.192
0.096
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