Consider the problem below: (Equation 1) 4 CO(g) + 4 H2O(l) ---> C4H8(l) + 4 O2(g) ΔH = 890.6 kJ/mol (Equation 2) CO2(g) ---> CO(g) + 1/2 O2(g) ΔH = 90.6 kJ/mol (Equation 3) C4H8(l) + 6 O2(g) ---> 4 CO2(g) + 4 H2O(l) ΔH = ??????? The ΔH for equation 3 is:______(express in kJ)

Chemistry
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Chapter1: Chemical Foundations
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Consider the problem below:

(Equation 1) 4 CO(g) + 4 H2O(l) ---> C4H8(l) + 4 O2(g) ΔH = 890.6 kJ/mol

(Equation 2) CO2(g) ---> CO(g) + 1/2 O2(g) ΔH = 90.6 kJ/mol

(Equation 3) C4H8(l) + 6 O2(g) ---> 4 CO2(g) + 4 H2O(l) ΔH = ???????

The ΔH for equation 3 is:______(express in kJ)

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Consider the problem below:

(Equation 1) 4 CO(g) + 4 H2O(l) arrow C4H8(l) + 4 O2(g) ΔH = 890.6 kJ/mol

(Equation 2) CO2(g) arrow C O(g) + 1/2 O2(g) ΔH = 90.6 kJ/mol

(Equation 3) C4H8(l) + 6 O2(g) arrow 4 CO2(g) + 4 H2O(l) ΔH = ???????

The ΔH for equation 3 is:______(express in kJ)

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