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- Consider the problem below: (Equation 1) 2 HF(g) ---> H2(g) + F2(g) ΔH = 537 kJ/mol (Equation 2) C(s) + 2 F2(g) ---> CF4(g) ΔH = -680. kJ/mol (Equation 3) 2 C(s) + 2 H2(g) ---> C2H4(g) ΔH = 52.3 kJ/mol (Equation 4) C2H4(g) + 6 F2(g) ---> 2 CF4(g) + 4 HF(g) ΔH = ??????? To find ΔH for equation 4 you must: Screen Reader Version Consider the problem below: (Equation 1) 2 HF(g) arrow H2(g) + F2(g) ΔH = 537 kJ/mol (Equation 2) C(s) + 2 F2(g) arrow CF4(g) ΔH = minus 680. kJ/mol (Equation 3) 2 C(s) + 2 H2(g) arrow C2H4(g) ΔH = 52.3 kJ/mol (Equation 4) C2H4(g) + 6 F2(g) arrow 2 CF4(g) + 4 HF(g) ΔH = ??????? To find ΔH for equation 4 you must: flip equation 1 only flip equation 2 only flip equation 3 only flip equation 1 and equation 2 only flip equation 1 and equation 3 only flip equation 2 and equation 3 only flip no equation

- Consider the problem below: (Equation 1) 2 HF(g) ---> H2(g) + F2(g) ΔH = 537 kJ/mol (Equation 2) C(s) + 2 F2(g) ---> CF4(g) ΔH = -680. kJ/mol (Equation 3) 2 C(s) + 2 H2(g) ---> C2H4(g) ΔH = 52.3 kJ/mol (Equation 4) C2H4(g) + 6 F2(g) ---> 2 CF4(g) + 4 HF(g) ΔH = ??????? To find ΔH for equation 4 you must: Screen Reader Version Consider the problem below: (Equation 1) 2 HF(g) arrow H2(g) + F2(g) ΔH = 537 kJ/mol (Equation 2) C(s) + 2 F2(g) arrow CF4(g) ΔH = minus 680. kJ/mol (Equation 3) 2 C(s) + 2 H2(g) arrow C2H4(g) ΔH = 52.3 kJ/mol (Equation 4) C2H4(g) + 6 F2(g) arrow 2 CF4(g) + 4 HF(g) ΔH = ??????? To find ΔH for equation 4 you must: flip equation 1 only flip equation 2 only flip equation 3 only flip equation 1 and equation 2 only flip equation 1 and equation 3 only flip equation 2 and equation 3 only flip no equation

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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- Consider the problem below:

(Equation 1) 2 HF(g) ---> H2(g) + F2(g) ΔH = 537 kJ/mol

(Equation 2) C(s) + 2 F2(g) ---> CF4(g) ΔH = -680. kJ/mol

(Equation 3) 2 C(s) + 2 H2(g) ---> C2H4(g) ΔH = 52.3 kJ/mol

(Equation 4) C2H4(g) + 6 F2(g) ---> 2 CF4(g) + 4 HF(g) ΔH = ???????

To find ΔH for equation 4 you must:

Screen Reader Version

Consider the problem below:

(Equation 1) 2 HF(g) arrow H2(g) + F2(g) ΔH = 537 kJ/mol

(Equation 2) C(s) + 2 F2(g) arrow CF4(g) ΔH = minus 680. kJ/mol

(Equation 3) 2 C(s) + 2 H2(g) arrow C2H4(g) ΔH = 52.3 kJ/mol

(Equation 4) C2H4(g) + 6 F2(g) arrow 2 CF4(g) + 4 HF(g) ΔH = ???????

To find ΔH for equation 4 you must:

  • flip equation 1 only
  • flip equation 2 only
  • flip equation 3 only
  • flip equation 1 and equation 2 only
  • flip equation 1 and equation 3 only
  • flip equation 2 and equation 3 only
  • flip no equation
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