14Consider the given descrete probability distribution,X :3P(x): 0.1 0.3 0.1 0.3 0.2calculate the P(X>3)CS Scanned with CamScanner4 5

Answer: From the given data, X : 1 2 3 4 5 P(X) : 0.1 0.3…

Answered: Consider the given descrete probability…

A First Course in Probability (10th Edition)

10th Edition

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Author:Sheldon Ross

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Chapter1: Combinatorial Analysis

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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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The discrete random variable X has the probability distribution given by: 1 2 3 4 P(X: 3v 2v V 0.4 a. Determine the following probability: P(X=1) = ? Answer in exact fraction or exact decimals b. What is the expected value of the random variable X? Answer in exact fraction or exact decimals c. What is the variance of the random variable X? Answer in exact fraction or exact decimals d. Find the expectation of the random variable Y, where Y = 3X – 2 Answer in exact fraction or exact decimals
The probability distribution of y, the number of accidents per 10 days of a diversion road in continuous days, is given by 1 3 4 f(y) 0.40 0.30 0.15 0.05 0.10 a. What is the probability of 1
The random variable X has the following probability distribution. -1 0 P(X=x) 0.20 0.50 0.30 Calculate E[X]. Round to two decimal places.
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In the following probability distribution, X represents the number of calls a telemarketer makes in a day, and the probability they make that many calls. П. 75 0.05 X 100 50 0.01 125 150 175 P(X) 0.15 0.20 0.30 a) Find P(X=175) b) Find E[X] ( c) Find the Variance and Standard Deviation ofX
The probability distribution for X and Y is shown by the table. Find the marginal distribution function value of X = 1. G(1) = X 2 3 1 0.06 0.10 0.04 2 0.10 0.12 0.13 3 0.15 0.19 0.11 Y
Suppose that X follows a binomial distribution with n = 100 and p = 0.1. If F(x) is the cumulative distribution function of the Standard Normal distribution. Then using the Normal approximation, the probability P(X = 16) is obtained by O a. F(2.17) - F(1.83) O b. F(1.83) - F(2.17) O c. F(16.5) + F(15.5) O d. F(17.0) - F(15.0)
Consider the following discrete probability distribution:- X 2 4 6 8 10 P(X = x) 0.3 0.3 0.2 0.1 0.1 Find: P(X < 8) E[X] Variance (X) If Y = 2X + 5, find E[Y]
For the given probability distribution: X: 0 P(X): 0.22 0.18 Find the given probability, P(X<2)? 1 CS Scanned with CamScanner 2 0.19 3 0.16 4 0.25
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An unfair die looks like an ordinary six-sided die but the outcomes are not equally likely. The probability distribution of the face value, XX, is as follows: xixi 1 2 3 4 5 6 Total P(X=xi)P(X=xi) 0.15 0.16 0.33 0.2 0.11 0.05 1 The expected value is computed, E[X]=3.11E[X]=3.11. To find the variance and standard deviation the following table was set up: xixi P(X=xi)P(X=xi) (xi−E[X])2(xi-E[X])2 (xi−E[X])2P(X=xi)(xi-E[X])2P(X=xi) 1 0.15 (1−3.11)2=(−2.11)2=4.4521(1-3.11)2=(-2.11)2=4.4521 4.4521⋅0.15=0.66784.4521⋅0.15=0.6678 2 (2−3.11)2=(−1.11)2=1.2321(2-3.11)2=(-1.11)2=1.2321 1.2321⋅0.16=0.19711.2321⋅0.16=0.1971 3 0.33 (3−3.11)2=(−0.11)2=(3-3.11)2=(-0.11)2= 0.0121⋅0.33=0.0040.0121⋅0.33=0.004 4 0.2 (4−3.11)2=(0.89)2=0.7921(4-3.11)2=(0.89)2=0.7921 0.7921⋅0.2=0.7921⋅0.2= 5 (5−3.11)2=(1.89)2=3.5721(5-3.11)2=(1.89)2=3.5721 3.5721⋅0.11=0.39293.5721⋅0.11=0.3929 6 0.05 8.3521⋅0.05=0.41768.3521⋅0.05=0.4176 E[X]=3.11E[X]=3.11 Total:…
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Consider the given descrete probability distribution, X : 1 2 3 P(x): 0.1 0.3 0.1 calculate the P(X>3) 4 5 0.3 0.2